The balanced equation for the given reaction:
C₆H₁₂O₆ (glucose) + 6O₂→ 6CO₂ + 6H₂O
So in the balanced equation the coefficients before glucose, oxygen, water and carbon dioxide are 1, 6, 6 and 6 respectively.
Therefore, the sum of the coefficients in the balanced equation
= 1 + 6 + 6 + 6
= 19
The correct answer is 19.
The mass of sodium chloride used <u>was 1.17 grams</u><u>.</u>
The mole fraction can be calculated by way of dividing the number of moles of 1 factor of an answer via the full variety of moles of all the additives of an answer. it is mentioned that the sum of the mole fraction of all the components inside the solution has to be the same as one.
mass of NaCl given = 64.9 g
mole = mass/molar mass
= 64.9 / 58.5
=<u> 1.109</u>
a mole fraction of water = 0.980
mole fraction of NaCl = 1 - 0.980
= <u>0.02</u>
1 mole of NaCl = 58.5
mass of NaCl = 58.5 × 0.02
=<u> 1.17 gram</u>
Mole Fraction describes the range of molecules contained within one aspect divided through the whole range of molecules in a given combination. it's miles quite beneficial whilst two reactive-natured components are mixed collectively.
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Answer:
Al2O3 + 6HCl --> 2AlCl3 + 3H2O
Explanation:
Al: 2
O: 3
H: 6
Cl: 6
Balanced on both sides.
Answer:
protons
Explanation:
the number of protons in a nucleus are equal to the number of atoms in an element.
Answer :
a) The concentration of 
at equilibrium is 0.08 m.
b) The concentration of 
at equilibrium is 0.26 m.
Solution :
The equilibrium reaction is,
![Fe^{3+}+SCN^-\rightleftharpoons [FeSCN]^{2+}](https://tex.z-dn.net/?f=Fe%5E%7B3%2B%7D%2BSCN%5E-%5Crightleftharpoons%20%5BFeSCN%5D%5E%7B2%2B%7D)
Initial concentration 0.230 0.410 0
At equilibrium (0.230 - x) (0.410 - x) x
Given x = 0.150
Therefore,
The concentration of = 0.230 - x = 0.230 - 0.150 = 0.08
The concentration of = 0.410 - x = 0.410 - 0.150 = 0.26
Thus, the concentration of at equilibrium is 0.08 m.
The concentration of at equilibrium is 0.26 m.
