Answer:
<h3>For two events A and B show that P (A∩B) ≥ P (A)+P (B)−1.</h3>
By De morgan's law
which is Bonferroni’s inequality
<h3>Result 1: P (Ac) = 1 − P(A)</h3>
Proof
If S is universal set then
<h3>Result 2 : For any two events A and B, P (A∪B) = P (A)+P (B)−P (A∩B) and P(A) ≥ P(B)</h3>
Proof:
If S is a universal set then:
Which show A∪B can be expressed as union of two disjoint sets.
If A and (B∩Ac) are two disjoint sets then
B can be expressed as:
If B is intersection of two disjoint sets then
Then (1) becomes
<h3>Result 3: For any two events A and B, P(A) = P(A ∩ B) + P (A ∩ Bc)</h3>
Proof:
If A and B are two disjoint sets then
<h3>Result 4: If B ⊂ A, then A∩B = B. Therefore P (A)−P (B) = P (A ∩ Bc) </h3>
Proof:
If B is subset of A then all elements of B lie in A so A ∩ B =B
where A and A ∩ Bc are disjoint.
From axiom P(E)≥0
Therefore,
P(A)≥P(B)
The approximate measure of angle T in the given diagram is 79°. The correct option is the first option 79°
<h3>Law of Cosines</h3>
From the question, we are to determine the approximate measure of angle T
From the law of cosines, we can write that
cosT = (s² + u² - t²)/2su
From the diagram,
s = 3.9 cm
u = 2.7 cm
t = 4.3 cm
Thus,
cosT = (3.9² + 2.7² - 4.3²)/2(3.9)(2.7)
cosT = (15.21 + 7.29 - 18.49)/21.06
cosT = 4.01/21.06
cosT = 0.1904
T = cos⁻¹(0.1904)
T = 79.02°
T ≈ 79°
Hence, the approximate measure of angle T in the given diagram is 79°. The correct option is the first option 79°
Learn more on Law of Cosines here: brainly.com/question/28081595
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X = 21
Hope this helped :)
The sum of the angles <6 and <3 must be 180. Since <3 and <1 are opposed to the top, their measure are equal. We need then to calculate the measure of angle >3 = 180 - <6 = 180-85=95
m(<1) = 95
Answer:
Step-by-step explanation:
look this solution