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3 years ago

5

The equations given on the graph is y=2x-4. Which of the following equations would create a system with this equation whose solu

tion would be (3,2).
(Photo Here)

Select one:

A. y= -2x+7

B. y= -12x+5

C. y= -4x+3

D. y= -x+5

1 answer:

Ghella [55]3 years ago

3 0

I guess answer is C y = -4x+3 when I do formula of Y= MX+b

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lilavasa [31]

Answer:

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Step-by-step explanation:

Let, $D=\frac{d}{dx}$

Now, us simplify the given differential equation and write it in terms of D,

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or, $3y''-4y'-4y=0$

or, $(3D^2-4D-4)y=0$

We have our auxiliary equation:

$3D^2-4D-4=0$

or, $(3D+2)(D-2)=0$

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Therefore our solution is,

$y=Ae^{2x}+Be^{- \frac{2}{3}x}$

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Applying the boundary conditions, we get,

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$2A-\frac{2}{3}B=0$

Solving them gives us,

$A=\frac{1}{4} ,B=\frac{3}{4}$

Hence,

$y=\frac{1}{4} e^{2x}+\frac{3}{4} e^{-\frac{2}{3}x }$

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Then shade till 4.5. Use closed circle at 4.5.

The graph is attached below.

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