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3 years ago

5

The equations given on the graph is y=2x-4. Which of the following equations would create a system with this equation whose solu

tion would be (3,2).
(Photo Here)

Select one:

A. y= -2x+7

B. y= -12x+5

C. y= -4x+3

D. y= -x+5

1 answer:

Ghella [55]3 years ago

3 0

I guess answer is C y = -4x+3 when I do formula of Y= MX+b

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EMERGENCY QUESTION! No Decimal answers plz!

telo118 [61]

Answer:

1,145,375 cm³

Step-by-step explanation:

Like with an earlier question you had, there is a chunk missing. If that chunk was filled in, this would be a 205 * 70 * 85 rectangular prism.

205 * 70 * 85

17,425 * 70

1,219,750

The cut out chunk is a 25 * 70 * 85 triangular prism.

1/2 (25 * 70 * 85)

1/2(2,125 * 70)

1/2(148,750)

74,375

Now that we know what the cut-out chunk is, subtract that from the first value we got.

1,219,750 -74,375

1,145,375 cm³

The volume of the Canadian Post mailbox is 1,145,375 cm³.

8 0

3 years ago

Read 2 more answers

Studentka2010 [4]

Can sb help with mines please

5 0

3 years ago

Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 98.8% of the pe

nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let $D^c$ be the event that a person don't have a disease

Let A be the event that a person is tested positive for that disease.

P(D|A) = Probability that someone has a disease given that he tests positive.

We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

We are also given that one person in 10,000 people has a rare genetic disease.

So, $P(D)=\frac{1}{10000}$

Only 0.4% of the people who don't have it test positive.

$P(A|D^c)$ = probability that a person is tested positive given he don't have a disease = 0.004

$P(D^c)=1-\frac{1}{10000}$

Formula: $P(D|A)=\frac{P(A|D)P(D)}{P(A|D)P(D^c)+P(A|D^c)P(D^c)}$

$P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}$

P(D|A)= $\frac{2470}{2471}$ =0.9995

P(D|A)= $0.9995$

A)The probability that someone who tests positive has the disease is 0.9995

(B)

$P(D^c|A^c)$ =probability that someone does not have disease given that he tests negative

$P(A^c|D^c)$ =probability that a person tests negative given that he does not have disease =1-0.004

=0.996

$P(A^c|D)$ =probability that a person tests negative given that he has a disease =1-0.988=0.012

Formula: $P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}$

$P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}$

$P(D^c|A^c)=0.99999$

B)The probability that someone who tests negative does not have the disease is 0.99999

8 0

3 years ago

Eremy works two jobs. He makes $8/hr working at a deli and $12/hr working for a landscaper. Let x represent the number of hours

bezimeni [28]

Answer:

A.) combinations of the hours he can work at the two jobs and earn at least $300

Step-by-step explanation:

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3 years ago

Read 2 more answers

Please I need help please please ILL MARK THE BRAINLIST

Olegator [25]

Answer:

1 2/5

Step-by-step explanation:

well the formula to find the permiter is 2(L+W)

7 0

3 years ago