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mel-nik [20]
2 years ago
6

The side of a square is Two raised to the seven halves power inches. Using the area formula A = s2, determine the area of the sq

uare.
Mathematics
2 answers:
AlladinOne [14]2 years ago
4 0

Answer:

Step-by-step explanation:

Area of a square = s²

s is the side length of the square

Given

s = 2^{7 1/2}

s = 2^15/2

Area = ( 2^15/2)²

Area = 2^15

Hence two area of the square is 2^15 inches

ololo11 [35]2 years ago
4 0

Answer:

A = 128 square inches

Step-by-step explanation:

A square is a figure with equal length of sides.

Given a square of side, s, 2^{\frac{7}{2} } inches.

Area of a square, A = length of side x length of side

                            = s x s

                            = s^{2}

Thus,

A = s^{2}

   = (2^{\frac{7}{2} } )^{2}

   = 2^{\frac{14}{2} }

   = 2^{7}

   = 128

A = 128 square inches

The are of the square is 128 square inches.

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A rectangle has a length of (x+4) feet and a width of (+7) feet. The expression 2(x+4)+2(x+7) represents the perimeter of the re
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Answer:

(x+4)+(x+4)+(x+7)+(x+7)

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Kipish [7]
Perpendicular means it’s opposite reciprocals for example : the slope is 2 then the perpendicular line’s slope would be -1/2 because it flips the number also makes it the opposite sign.

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7 0
3 years ago
If C4=15 and C7=14, what is the result of the logical expression C4&gt;C7 true or false
kvasek [131]
The answer is True because just plug in the numbers

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C4>C7

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3 0
2 years ago
How many times does the graph of 4x = 32 - x2 cross the x-axis?
garik1379 [7]

Answer:

The graph crosses the x-axis 2 times

The solutions are  x = -8  &  x = 4

Step-by-step explanation:

Qaudratics are in the form ax^2 + bx+ c

Where a, b, c are constants

Now, let's arrange this equation in this form:

4x=32-x^2\\x^2+4x-32=0

Where

a = 1

b = 4

c = -32

We need to know the discriminant to know nature of roots. The discriminant is:

D=b^2-4ac

If

  • D = 0 , we have 2 similar root and there is 2 solutions and that touches the x-axis
  • D > 0,  we have 2 distinct roots/solutions and both cut the x-axis
  • D < 0,  we have imaginary roots and it never cuts the x-axis

Let's find value of Discriminant:

D=b^2-4ac\\D=(4)^2 -4(1)(-32)\\D=144

Certainly D > 0, so there are 2 distinct roots and cuts the x-axis twice.

We get the roots/solutions by factoring:

x^2+4x-32=0\\(x+8)(x-4)=0\\x=4,-8

Thus,

The graph crosses the x-axis 2 times

The solutions are  x = -8  &  x = 4

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3 years ago
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