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Sphinxa [80]
3 years ago
14

Sarah leans a 20 ft ladder against

Mathematics
1 answer:
Katarina [22]3 years ago
8 0

Answer:

(a) 14

this is what i got

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Y = 3x<br> x + y = 52<br><br> substitution method <br> help quick <br> show all work
AfilCa [17]

Answer:

x + 3x = 52 \\ 4x = 52 \\ x = 13 \\ y = 3x = 3 \times 13 = 39

8 0
3 years ago
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

__

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0
3 years ago
Solve y+4x=12 3y=8-12x
attashe74 [19]
\left \{ {{y+4x=12} \atop {3y=8-12x}} \right. \\\\ \left \{ {{y=12-4x} \atop {3y=8-12x}} \right. \\\\3(12-4x)=8-12x\\\\36-12x=8-12x\\\\-12x+12x=8-36\\\\0\neq28\\\\There\ are\ no\ solutions.
6 0
3 years ago
What is 7/6 ÷ 4 in simplest form
serg [7]
\frac{7}{6} \div 4= \frac{7}{6} \times \frac{1}{4} = \frac{7\times 1}{6\times 4} = \frac{7}{24}

7/24 is your answer :)
7 0
3 years ago
Read 2 more answers
How old do you got to be to drop out
bazaltina [42]

Answer:

Step-by-step explanation:

high school with pariantal consent

6 0
3 years ago
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