4x3x8x7x9x3x6x7x7x3x9x7x2x3x6x9x9x2x4x2x3x2x8 = ????⇒∈ pls answer ill mark brainly

What is the distance points for (2,-2) and (0,-9)

Ksivusya [100]

The distance between two points (2,-2) and (0,-9) is 7.3 units, which is obtained by graphical method and formula method.

Step-by-step explanation:

The given is,

Two points are (2,-2) and (0,-9)

Step:1

By graphical method,

For two points (2,-2) and (0,-9)

First point (2,-2)

The values of x=2 and y=-9 noted in the graph

Second point (0,-9)

The values of x=0 and y=-9 noted in the graph

Now join the two points, measure the distance between the two points,

Distance between points are 7.3 units.

( OR )

Step:1

By formula method,

Distance = $\sqrt{(x_{2}- x_{2}) ^{2}+ (y_{2}-y_{1}) ^{2} }$

Where,

( 2,-2) are ( $x_{1},y_{1}$ )

(0,-9) are ( $x_{2},y_{2}$ )

From the values,

= $\sqrt{(0- 2) ^{2}+ (-9+2) ^{2} }$

= $\sqrt{(- 2) ^{2}+ (-7) ^{2} }$

= $\sqrt{4+49 }$

= $\sqrt{53}$

= 7.280

≅ 7.3

Distance = 7.3

Result:

The distance between two points (2,-2) and (0,-9) is 7.3 units, which is obtained by graphical method and formula method.

5 0

3 years ago

Write an algebraic expression for the word phrase. 6 more than the difference of W and 3.

TEA [102]

The answer is going to be C

5 0

3 years ago

What is the greatest common factor of 44c^5, 22c^3 and 11c^4

Alexxandr [17]

$\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3$

Solution:

Given that, we have to find the greatest common factor of $44c^5, 22c^3 , 11c^4$

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

$\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}$

First find the GCF of numbers and then find the GCF of variables and then multiply them together

Step 1: GCF of 44, 22 and 11

The factors of 11 are: 1, 11

The factors of 22 are: 1, 2, 11, 22

The factors of 44 are: 1, 2, 4, 11, 22, 44

11 is the greatest factor that is common in above three list

Then the greatest common factor is 11

$\text{ Step 2: GCF of }c^5, c^3 , c^4$

$c^5 = c^3 \times c^2\\\\c^3 = c^2 \times c^1 \text{ or } c^3\\\\c^4 = c^3 \times c^1$

Thus the greatest common factor is $c^3$

Step 3: Multiply the GCF of 44, 22, 11 and GCF of $c^5, c^3 , c^4$

$\text{ GCF of } 44c^5, 22c^3 , 11c^4 = 11 \times c^3 = 11c^3$

Thus $\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3$

8 0

3 years ago

PLEASE HELP!!!!!!!! (ALGEBRA II)

qwelly [4]

Answer:

-4 4 4.5 8 20.5 32

Step-by-step explanation:

f $\circ$ g(x) = f(g(x))

Given, f(x) = 2x²

and g(x) = x - 2

Now f(g(x)) = f(x - 2) = 2(x - 2)²

We know that (a - b)² = a² - b² + 2ab

Using this we expand f(g(x)). We get:

f(g(x)) = 2{x² - 4x + 4}

Similarly, g(f(x)) = g(2x²) = 2x² - 2

Now, f(g(-2)) = 2[(-2)² - 4(-2) + 4] = 2(16) = 32.

Also, g(f(-2)) = 2[(-2)² - 2] = 2(2) = 4.

f(g(3.5)) = 2{(3.5)² -4(3.5) + 4} = 2[12.25 - 14 + 4] = 2(2.25) = 4.5.

g(f(3.5)) = 2{(3.5)² -2} = 2{12.25 - 2} = 2(10.25) = 20.5.

f(g(0)) = 2{0 - 4(0) + 4} = 2(4) = 8.

g(f(0)) = 2{0 - 2} = 2(-2) = -4.

Arranging them in ascending order, we get:

-4 4 4.5 8 20.5 32 would be the sequence.

5 0

4 years ago

Choosing a member of the math club and a member of the science club?

Alexus [3.1K]

Huh I am quite confused

8 0

3 years ago

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