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2 years ago

A parking lot in the shape of a parallelogram has a length of

Mathematics

1 answer:

OLga [1]2 years ago

8 0

Answer:

C. 1 centimeter = 30 meters

$10 \: cm = 300 \: m \\ 1 \: cm = ( \frac{1}{10} \times 300) \: m \\ = 30 \: m \\ \\ 5 \: cm = 150 \: m \\ 1 \: cm = 30 \: m$

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I don't understand the bottom questions. Please help, it's due for tomorrow!

Elena-2011 [213]

I am giving the answers only.

2/5

4/7

5/11

1/5

2/3

3/5

2/15

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3 0

3 years ago

Find an equation of the parabola with focus (2, −3) and directrix y = 1.

Likurg_2 [28]

Answer:

Step-by-step explanation:

The correct option is option (C).

The required equation of the parabola is

Step-by-step explanation:

Formula:

The distance of a point (x₁,y₁) from a line ax+by+c=0 is

The distance between two points (x₁,y₁) and (x₂,y₂) is

Given that, the focus of the parabola is (2,3) and directrix y= - 1.

We know that, a parabola is the locus of points that equidistant from the directrix and the focus.

Let any point on the parabola be P(x,y) .

The distance of P from the directrix is

=y+1

The distance of the point P from the focus (2,3) is

According to the problem,

The required equation of the parabola is

5 0

2 years ago

IS THIS RIGHT???????????????????

Mnenie [13.5K]

Answer:

yes it is correct 10% is the answer

3 0

2 years ago

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(pls help!!) Find an equation in point-slope form for the line having the slope m=2 and containing the point (4,5).

ANTONII [103]

Y-5=2(x-4)

That’s point slope form

6 0

3 years ago

Use a half-angle identity to find the exact value of tan 22.5°.

dusya [7]

Answer:

$\sqrt{2} -1$

Step-by-step explanation:

22.5 degrees is half of 45 degrees (special angle for which we know exactly the value of all three basic trigonometric functions (sine, cosine, and tangent).

So we start recalling the formula for tangent of a half angle: $tan(\frac{\alpha }{2} )= \frac{1-cos(\alpha) }{sin(\alpha) }$

We need just the values of:

$sin(\alpha )=sin(45^o)=\frac{\sqrt{2} }{2}$

and of

$cos(\alpha )=cos(45^o)=\frac{\sqrt{2} }{2}$

to answer the question. Then, we use those values in the original formula for tangent of a half angle:

$tan(\frac{\alpha }{2} )= \frac{1-cos(\alpha) }{sin(\alpha) }\\tan(22.5^o)=\frac{1-\frac{\sqrt{2} }{2} }{\frac{\sqrt{2} }{2}} =\frac{2-\sqrt{2} }{\sqrt{2} } =\frac{2\sqrt{2}-2 }{2} =\sqrt{2} -1$

3 0

3 years ago

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