V =πr^2h
v= 3.14×27×27×15
v=34335.9
v= 34336
X=4 is the answer to this question
#13:
s² = 144
√(s²) = √144
|s| = 12
s = -12 OR s = 12
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#15 (not sure what letter you used so I went with 'g')
(g-6)² = 25
√[(g-6)²] = √25
|g-6| = 5
g - 6 = -5 OR g - 6 = 5
g = 1 OR g = 11
<u>|4x + 2| + 6 = 0</u>
Subtract 6 from each side: |4x + 2| = -6
But the absolute value of a number is always positive.
No value of 'x' can ever make |4x + 2| negative.
So the equation has <em>no solution</em>.