What physical quantity do you obtain when you divide molar mass (Mm) by molar volume (Vm)?
1 answer:
Answer:
The mass density (ρ)
Explanation:
The molar volume (Vm) is the volume that a mole of an element or compound occupies at standard temperature and pressure STP
The molar volume can be found as follows;
Where;
Mm = The molar mass
ρ = The mass density
The molar mass (Mm) of an element or a compound is the ratio of the mass of the element or compound to the amount of the element or compound in the given mass
The mass density, ρ, of an element or a compound is the mass of a unit volume of the element or compound
Therefore, we have;
When we divide the molar mass (Mm) by the by the molar volume (Vm), we obtain the mass density (ρ).
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<u>Answer :</u>
(a) The Initial temperature of the steam is 247.557°C
(b) The enthalpy change per unit mass of the steam is -1771 kJ/kg
(c) The final pressure is 1555 kPa, and the liquid vapor mixture contains small mass of vapor.
<u>Explanation :</u>
From the given statements, we know
Initial steam pressure () = 3.5 MPa
Degree of Super heat = 5°C
Saturation Temperature () = 242.557°C [From Steam Table]
Now, the Initial temperature () of steam is given by-
=
+ Degree of Superheat
= 242.557 + 5 = 247.557°C
(b)To find: The enthalpy change per unit mass of the steam is
We know enthalpy (h) change is given by
Δh = –
From steam Table, properties of the gas at state 1 and state 2
= 2821.1 kJ/kg
= 1049.7 kJ/kg
On substituting the values, we get
or, Δh = 1049.7 - 2821.1 = -1771 kJ/kg
(c) To Find: The final pressure of the liquid vapor mixture contains small mass of vapor.
We find that the gas at the final position, i.e., at position 3
Final Temperature () = 200°C [Given] ……………………………..(1)
Specific Volume () = Specific Volume (
) = 0.00123
/kg ….....(2)
Using steam table for corresponding values of (1) and (2), we get
Final Pressure = 1555 kPa
Dryness fraction () = 0.0006.
Answer:
the radius of bigger loop = 6 cm
Explanation:
given,
two concentric current loops
smaller loop radius = 3.6 cm
]current in smaller loop = 12 A
current in the bigger loop = 20 A
magnetic field at the center of loop = 0
Radius of the bigger loop = ?
now, on solving
=
= 6 cm
hence, the radius of bigger loop = 6 cm