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jasenka [17]
3 years ago
8

Fireworks change _____ into ______ and ________ energy.

Physics
1 answer:
Liula [17]3 years ago
4 0
Fireworks change chemical into thermal and radiant energy
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Which is capeble of housing astronaughts while they conduct reasearch
dusya [7]

Answer:

2

Explanation:

2

5 0
2 years ago
Read 2 more answers
A tank of gasoline (n = 1.40) is open to the air (n = 1.00). A thin film of liquid floats on the gasoline and has a refractive i
klio [65]

Answer:

1.08

Explanation:

This is the case of interference in thin films in which interference bands are formed due to constructive interference of two reflected light waves , one from upper layer and the other from lower layer . If t be the thickness and μ be the refractive index then

path difference created will be 2μ t.

For light coming from rarer to denser medium , a phase change of π occurs additionally after reflection from denser medium, here, two times, once from upper layer and then from the lower layer ,  so for constructive interference

path diff = nλ , for minimum t , n =1

path diff = λ

2μ t. =  λ

μ = λ / 2t

= 626 / 2 x 290

= 1.08

5 0
3 years ago
A six pack of your favorite beverage (12 fl. oz. cans, assumed to have the same characteristics as water) is placed in a cooler
nasty-shy [4]

Answer:

Q = 169 BTU

Explanation:

As we know that volume is given as

V = 12 Fl oz

so it is given in liter as

V = 12 fl oz = 0.355 Ltr

now we have six pack of such volume

so total volume is given as

V = 6\times 0.355 Ltr

V = 2.13 ltr

so its mass is given as

m = 2.13 kg

now the change in temperature is given as

\Delta T = 70 - 34 = 36 ^oF

\Delta T = 20^oC

now the heat given to the liquid is given as

Q = ms\Delta T

Q = 2.13(4186)(20)

Q = 1.78 \times 10^5 J

Q = 169 BTU

4 0
2 years ago
A horizontal line in a distance-time graph implies that,
Citrus2011 [14]
The object is at rest is the answer.
6 0
3 years ago
If the temperature is held constant during this process and the final pressure is 671 torr , what is the volume of the bulb that
MariettaO [177]

Complete Question

The  complete question is shown on the first uploaded image  

Answer:

Explanation:

From the question we are told that

   The initial pressure of the gas is  P_1 =  1.50 \  atm

   The volume of the second bulb is  V_2 =  0.800 \  L

   The  final pressure of the gas is  P_2 =  671 \ torr =  \frac{671 }{ 760}  =  0.883 \ atm

Let the unknown volume be represented as V_1 =  V \   L

Generally from Boyle's law we have that

      P_1 *  V_1 =  P_2 * V_2

=>   1.50 *  V =   0.883  * 0.800

=>   V  = 0.479 \ L

         

4 0
3 years ago
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