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3 years ago

Help resolve this please

Mathematics

2 answers:

Romashka [77]3 years ago

7 0

I cant see the picture :(

Leokris [45]3 years ago

5 0

Answer:

this is late but 1176?

Step-by-step explanation:

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Find the value of x. 50 points

notka56 [123]

The answer is 138
Because the angle is 180 and what I did was 2 x 21 = 42 and I did 180-42 equals to 138

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1 year ago

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Determine if the lines are parallel, perpendicular, or neither x-3y= 15 and y = -3+4

Alina [70]

If the second equation is y=-3x+4 then they would be parallel and I found that by turning the first equation into y=mx+b and you subtract x from both sides of the equation and get -3y=-x+15 and then you divide both sides of the equation by -3 to get the y by itself and that turns into y=1/3x-5 and since 1/3 is the reciprocal of -3 they are perpendicular.

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3 years ago

PLEASE ANSWER ASAP!!!!

Arlecino [84]

We'll use the notation $\textrm{Arcsin } x$ for the principal value and $\arcsin x$ for all the values:

$\arcsin x = \textrm{Arcsin } x + 2\pi k \textrm{ or } (\pi - \textrm{Arcsin }x) + 2\pi k \quad \textrm{ integer } k$

Part I

$\sin(\theta/2) = \frac 1 2$

$\theta/2 = \arcsin \frac 1 2$

Part II. In our range we can write

$\sin(\theta/2) = \sin(\frac \pi 6)$

$\theta/2 = \frac \pi 6 \textrm{ or } \theta /2 = \pi - \frac \pi 6 = \frac{5\pi}{6}$

Part III.

$\theta = \frac \pi 3 \textrm{ or } \theta = \frac{5\pi}{3}$

Part IV.

$\theta/2 = \frac \pi 6 + 2\pi k \textrm{ or } \theta = \frac{5 \pi}{6} + 2\pi k \quad \textrm{integer } k$

$\theta = \frac \pi 3 + 4 \pi k \textrm{ or } \theta = \frac{5 \pi}{3} + 4\pi k \quad \textrm{integer } k$

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2 years ago

The distance d, in centimeters, that a diving board bends below its resting position when you stand at its end is dependent on y

kaheart [24]

Answer:

d(1) = -3 and d(2)= -28

Step-by-step explanation:

Given that the distance d, in centimeters, that a diving board bends below its resting position when you stand at its end is dependent on your distance x, in meters, from the stabilized point

$d(x)=-4x^3+x^2$