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Masja [62]
2 years ago
14

Shira’s Shoes sold 875,000 pairs of sandals in June, which was 70% of the total number of shoes sold. How many shoes did the com

pany sell in June? Analyze Emily’s calculations. What error did she make?
Computers and Technology
2 answers:
Angelina_Jolie [31]2 years ago
8 0

Explanation:

Emily solved for a part when she should have solved for the whole. 875,000 should be the numerator of the equivalent ratio. 70 x 12,500 is 875,000. So the answer is 100 x 12,500 which is 1,250,000.

Iteru [2.4K]2 years ago
6 0

Answer:

Emily solved for a part when she should have solved for the whole. 875,000 should be the numerator of the equivalent ratio. 70 x 12,500 is 875,000. So the answer is 100 x 12,500 which is 1,250,000.

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Which element is included in the shot breakdown storyboard? Which element is included in the shot breakdown storyboard?
VladimirAG [237]

Answer: jump out

Explanation:

Took the test and it was correct

5 0
3 years ago
Create a java class for Bank Accounts with these public String attributes: ownerName, acctNbr and these private double attribute
Readme [11.4K]

Answer:

public class BankAccounts

 {

   public String ownerName;

   public String acctNbr;

   private double debits;

   private double credits;

   public BankAccounts(String ownerNm, String acNum)

  {

    debits = 0;

    credits = 0;

    ownerName = ownerNm;

    acctNbr = acNum;

  }

public void addDebit(double debitAmt)

  {

    if(credits > (debits + debitAmt))

      debits = debits + debitAmt;

    else

      System.out.println("Insufficient balance");

}

   public void addCredit(double creditAmt)

  {

    credits = credits + creditAmt;

  }

public double getBalance()

  {

    double balance = 0;

    if((credits - debits) > 0)   // return the value if there is actually some balance left.

      balance = credits - debits;

    return balance;   //returns 0 if credits are lesser or equal to debits

  }

 }

Explanation:

Here class name is <em>BankAccounts </em>which can be used to create a new bank account whenever any user wants to open a bank account. This class will help to track any new account opening, debits and credits operations carried out on that account.

We have a constructor here, which accepts 2 arguments i.e. Bank account <em>Owner Name</em> and <em>Account Number</em>. The constructor also sets the values of <em>debits </em>and <em>credits</em> as 0.

The methods <em>addDebit()</em>, <em>addCredit()</em> and <em>getBalance()</em> help to perform Debit and Credit operations on the account.

NOTE: The method <em>getBalance()</em> returns a positive value only when credits are greater than debits.

The method <em>addDebits()</em> can add debits only as the condition that the credits are greater than the resultant debits.

The code for class <em>BankAccounts</em> is hereby attached.

Download java
4 0
3 years ago
// In this exercise, you will be given a variable, it will be called: value
rjkz [21]

Answer:

import java.util.Scanner;

public class Solution {

   public static void main(String args[]) {      

     Scanner scan = new Scanner(System.in);

     System.out.println("Enter your value");

     int value = scan.nextInt();      

     greaterThanFive(value);

   }  

   public static void greaterThanFive(int userInput){

       System.out.println(userInput > 5);

   }

}

Explanation:

The first line import the Scanner which is use to enable to accept user input.

The class is defined as Solution in the next line. The main method is declared in the next line which signify the beginning of the program.

Then, a scanner object is declared called scan in the next line. Then a prompt is display to the user to input a value. The user input is stored in the variable value. The value is then passed to the method greaterThanFive.

The method greaterThanFive is declared and have just one parameter, the userInput. Inside the method, we output if the userInput is greater than 5 using the logical operator (>).

8 0
3 years ago
Why would you use a custom filter?
Angelina_Jolie [31]

Answer:By specifying conditions, you can create custom filters that narrow down the data in the exact way that you want. You do this by building a filter. If you've ever queried data in a database, this will look familiar to you. Point to either Number Filters or Text Filters in the list.

Explanation:

5 0
3 years ago
Piecewise functions are sometimes useful when the relationship between a dependent and an independent variable cannot be adequat
Andru [333]

Answer:

//Set a piecewise function v(t).

function v = vpiece(t)

//Set the condition first for t.

if ((0<=t)and(t<=8))  //Set if condition

// first equation of velocity.

   v = 10*t^2 - 5*t;

//Set the condition second for t.

elseif((8<=t)and(t<=16))  //Set elseif condition

//second equation of velocity.

v = 624 - 5*t;

//set the condition third for t.

elseif((16<=t)and (t<=26))  //Set elseif condition  

//third equation of velocity.

v = 36*t + 12*(t - 16)^2;

//Set the fourth condition for t.

elseif t>26

//fourth equation of velocity.

v = 2136*exp(-0.1*(t-26));

//Last condition.

else

//fifth equation of velocity.

v = 0;

//End of the function v.

end

//set a variable and initialize it to 0.

a=0;

//Starting the loop.

for j = -5: 0.5 : 70

//Increment the value of a by 1.

a = a + 1;

t(a) = j;

v(a) = vpiece(t(a));

//End of for loop.

end

//Plot the graph between t and v.

plot(t,v)

//Write the label for the x-axis.

xlabel('t')

//Write the label for the y-axis.

ylabel('velocity')

//Write the title of the plot.

title('Plot of velocity vs t')

Explanation:

Firstly, we set the piecewise method.

Then we set the first condition, after that we apply the condition of velocity.

Then we set the second condition, after that we apply the condition of velocity.

Then we set the third condition, after that we apply the condition of velocity.

Then we set the fourth condition, after that we apply the condition of velocity.

Then we set the last or fifth condition, after that we apply the condition of velocity.

Then we set the variable "a" to 0.

Then start the loop and increase the value by 1.

And after all, we write the title of the plot.

8 0
3 years ago
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