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3 years ago

Even though I answered this question all I just want to make sure

Physics

2 answers:

Yuri [45]3 years ago

7 0

Answer:

I think it's an object in rest will stay in rest and an object at motion will stay at motion unless acted on by an outside force

EastWind [94]3 years ago

4 0

yes this is correct good job

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A uniform, 0.0300-kg rod of length 0.400 m rotates in a horizontal plane about a fixed axis through its center and perpendicular

AURORKA [14]

Answer:

A) ω₂ = 28 rev/min

B) ω_3 = 28 rev/min

Explanation:

A) Initial moment of inertia (I₁) is the rod's own ((1/12)ML²) plus that of the two rings (two lots of mr² if we treat each ring as a point mass).

Thus;

I₁ = ((1/12)ML²) + 2(mr²)

Where;

M is mass of rod = 0.03 kg

L is length of rod = 0.4m

m is mass of small rings = 0.02 kg

r is radius of small rings = 0.05 m

Thus;

I₁ = ((1/12) x 0.03 x 0.4²) + 2(0.02 x 0.05²)

I₁ = 0.0021 kg.m²

Now, when the rings slide and reach the ends of the rod i.e at r = L/2 = 0.4/2 = 0.2m from axis, the new Moment of inertia is;

I₂ = ((1/12) x 0.03 x 0.4²) + 2(0.02 x 0.2²)

I₂ = 0.0036 kg.m²

From conservation of angular momentum, we know that:

I₁ω₁ = I₂ω₂

We are given ω₁ = 48 rev/min.

Thus; plugging in the relevant values;

0.0021 x 48 = 0.0036ω₂

0.1008 = 0.0036ω₂

ω₂ = 0.1008/0.0036

ω₂ = 28 rev/min

b) For this, we have the same scenario as the case above where the ring just reaches the ends of the rods.

Thus,

I₂ω₂ = I_3•ω_3

So,0.0021 x 48 = 0.0036ω_3

ω_3 = 28 rev/min

7 0

3 years ago

What is the temperature increase of 4.0 kg of water when heated by an 800-W immersion heater for 10 min? (cw = 4 186 J/kg⋅°C)

Llana [10]

Answer:

option C

Explanation:

given,

mass of water = 4 Kg

Water is heated to = 800 W

time of immersion = 10 min

= 10 x 60 = 600 s

using equation of specific heat

Q = m S ΔT

S is the specific heat capacity of water which is equal to 4182 J/kg°C.

and another formula of heat

Q = Pt

now,

P t = m S ΔT

800 x 600 = 4 x 4182 x ΔT

ΔT = 29° C

temperature increased is equal to ΔT = 29° C

Hence, the correct answer is option C

3 0

3 years ago

What is the frequency of a wave that has a wave speed of 80 m/s and a wavelength of 0.20 m?

Naya [18.7K]

Speed=frequency*wavelength, so frequency=speed/wavelength. frequency=80*0.2
Frequency = 16 Hz

4 0

4 years ago

A toy cork gun contains a spring whose spring constant is 10.0N/m. The spring is compressed 5.00cm and then used to propel a 6.0

valentina_108 [34]

Answer:

The muzzle velocity of this cork is 2 m/s.

Explanation:

It is given that,

Spring constant of the spring, k = 10 N/m

Mass of the cork, m = 6 g = 0.006 kg

Initial position of the spring, x = 5 cm = 0.05 m

Final position of the spring, x' = 1 cm = 0.01 m

According to the law of conservation of energy, the initial potential energy of the spring is equal to the sum of final spring potential energy and the kinetic energy of cork such that,

$\dfrac{1}{2}kx^2=\dfrac{1}{2}kx'^2+\dfrac{1}{2}mv^2$

v is the muzzle velocity of this cork.

$kx^2=kx'^2+mv^2$

$v=\sqrt{\dfrac{k(x^2-x'^2)}{m}}$

$v=\sqrt{\dfrac{10\times ((0.05)^2-(0.01)^2)}{0.006}}$

v = 2 m/s

So, the muzzle velocity of this cork is 2 m/s. Hence, this is the required solution.

4 0

4 years ago

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What can change shape and volume? PLz help :)

Rasek [7]

Gas has no certain shape However, its Volume can change with Differences in Heat and Pressure.

6 0

3 years ago

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