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3 years ago

What is the temperature increase of 4.0 kg of water when heated by an 800-W immersion heater for 10 min? (cw = 4 186 J/kg⋅°C)

Physics

1 answer:

Llana [10]3 years ago

3 0

Answer:

option C

Explanation:

given,

mass of water = 4 Kg

Water is heated to = 800 W

time of immersion = 10 min

= 10 x 60 = 600 s

using equation of specific heat

Q = m S ΔT

S is the specific heat capacity of water which is equal to 4182 J/kg°C.

and another formula of heat

Q = Pt

now,

P t = m S ΔT

800 x 600 = 4 x 4182 x ΔT

ΔT = 29° C

temperature increased is equal to ΔT = 29° C

Hence, the correct answer is option C

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Mice21 [21]

Answer:

The displacement in t = 0,

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Explanation:

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λ = v / f

λ = 32 m/s / 40 Hz = 0.8

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Answer:

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Explanation:

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alexgriva [62]

Answer:

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$y = 30sin\frac{\pi}{6}t + 45$

Explanation:

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alekssr [168]

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