LAN (Local Area Network)
<span>Basically, to be precise, Intranet is
an extension of LAN in which IP services like HTTP, TCP/IP and several other
standard protocols are added. Intranet is a private internet network that is
used to add internet like services in an internal LAN.</span>
Explanation:
in fourth generation microprocessor was developed.
may it helped u
Answer:
<em>C++</em>
////////////////////////////////////////////////////////////////////////////////////////////////////////
#include <iostream>
#include <vector>
using namespace std;
int main() {
vector<int> v;
int n = 1;
while (n != 0) {
cout<<"Enter an integer, the input ends if it is 0: ";
cin>>n;
v.push_back(n);
}
cout<<endl;
///////////////////////////////////////////////////////////
int sum = 0;
int num_positives = 0, num_negatives = 0;
for (int i=0; i<v.size()-1; i++) {
if (v[i] > 0)
++num_positives;
else
++num_negatives;
sum = sum + v[i];
}
//////////////////////////////////////////////////////////
cout<<"The number of positives is "<<num_positives<<endl;
cout<<"The number of negatives is "<<num_negatives<<endl;
cout<<"The total is "<<sum<<endl;
cout<<"The average is "<<(float)sum/(v.size()-1);
///////////////////////////////////////////////////////////
return 0;
}
Answer:
for (scores.Entry<String, Integer> entry : scores.entrySet()) {
int value=0; String key="Rambo";
String k = entry.getKey();
int v = entry.getValue();
if (v>value)
{
value =v;
}
else
{
value=value;
}
}
for( scores.Entry<String, Integer> entry : scores.entrySet())
{
if( entry.getValue()==value)
System.out.println("Key = " + entry.getKey() + ", Value = " + entry.getValue());
}
Explanation:
The above scores are an object of Map type. And this is a parameter of findUopStudent function. So scores is a Map, and entry is an item. And we get its key and value. Now we compare each value using senteniel method and find the maximum value. Now we iterate through the scores using for the look and check the value of each entry against the maximum value found, and we print out the entry with maximum value. And that is the top student, which is required.
Answer:
johnsons rule minimizes total idle time for both machines or work centers. What technique is used when setup times at a workstation are sequence dependent? determine the total time of each job sequence permutation considering the setup time and choose the best (lowest) time.
Explanation:
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