Answer:
The difference quotient for
is
.
Step-by-step explanation:
The difference quotient is a formula that computes the slope of the secant line through two points on the graph of <em>f</em>. These are the points with x-coordinates x and x + h. The difference quotient is used in the definition the derivative and it is given by

So, for the function
the difference quotient is:
To find
, plug
instead of 

Finally,


The difference quotient for
is
.
<h2>
Greetings!</h2>
Answer:
Angle A is 118°
Step-by-step explanation:
All angles in a circle add up to 180, so this means that all the measurements of the three angles add to 180:
x + 2x + 13 + x - 8 = 180
Clean it up:
3x + x + x + 13 -8
5x -5 = 180
To isolate the 5x, you need to move the +5 over to the other side, making it a negative 5:
5x = 180 - 5
5x = 175
Now divide each side by 5 to get the value of 1x:

x = 35
So angle A is:
3x + 13
3(35) + 13 = 118
<h3>So angle A is 118°</h3>
<h2>Hope this helps!</h2>
So you write into the table that x = 1 then y will equal 1*1.5 which equal to 1.5. So under x = 1 in y table you write y = 1.5, and so on
Answer:
3x²-29x+4
Step-by-step explanation:
3x²-x-4=-30x
0=-30x-3x²+x+4
0=-3x²-29x+4
A. Every month Population will increase by a factor of 0.84%.
B. Every 3 months Population will increase by a factor of 2.5%.
C. Increase in population in every 20 months is 10% + 6.72% = 16.72%.
<u>Step-by-step explanation:</u>
Here, we have number of employees in a company has been growing exponentially by 10% each year. So , If we have population as x in year 2019 , an increase of 10% in population in 2020 as
which is equivalent to
.
<u>A.</u>
For each month: We have 12 months in a year and so, distributing 10% in 12 months would be like
. ∴ Every month Population will increase by a factor of 0.84%.
<u>B.</u>
In every 3 months: We have , 12 months in a year , in order to check for every 3 months
and Now, Population increase in every 3 months is
. ∴ Every 3 months Population will increase by a factor of 2.5%.
<u>C.</u>
In every 20 months: We have , 12 months in a year in which increase in population is 10% . Left number of moths for which we have to calculate factor of increase in population is 20-12 = 8. For 1 month , there is 0.84% increase in population ∴ For 8 months , 8 × 0.84 = 6.72 %.
So , increase in population in every 20 months is 10% + 6.72% = 16.72%.