Question

Dose anyone know how to solve this?

Answer 1

Answer:

1. 3x³-6x²
2. 3x²+x-2
3. -16

Step-by-step explanation:

For 1: Multiply both functions together, expand, then simplify

(x-2)(3x²) = 3x³-6x²

For 2: Just add both functions together

For 3: Subtract both functions to get -3x²+x-2 and substitute x with -2

-3(-2)²-2-2 = -16

Answer 2

Answer:

$f(x) = x - 2\\g(x) = 3x^2\\(f \cdot g)(x) = f(g(x))$

             $=f(3x^2) \\= (3x^2) - 2 \\= 3x^2 - 2$

$(f+g)(x) = f(x) + g(x)$

              $=(x-2) + (3x^2)\\= 3x^2 + x - 2$

$(f-g)(-2) = f(-2) - g(-2)$

                 $= ((-2) - 2) - ( 3 (-2)^2)\\=(-2-2) - (3 \times 4)\\=-4-12\\=-16$