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klemol [59]
3 years ago
15

A worker gets $9/hr for a regular work day and $13.50/hr for additional hours. If he was paid $114.75 for an 11hr work day, how

long is a regular work day?
Mathematics
1 answer:
Anika [276]3 years ago
4 0

1. I did 9x8 since you usually work 8 hours a day but did not give answer, so I add or subtracted 0.5 to 8.

2. i did 9*7.5=67.5 , keep in mind that he worked for 11 hrs that day so 11-7.5=3.5 hours left

3. then I subtracted 67.5 from 114.75 and got 47.25

4. I divided 3.5 by 47.25 and got 13.5

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Marina CMI [18]

Answer:

Hey ,the last one 2*2*2*3*5*5+2*2*2*2*2=8*3*25+36=600+36=636

Hope it helps

5 0
2 years ago
X=−4a 2 +3ab+12b 2 Y=9a 2 +ab−7b 2 ​ Y+X=Y+X=Y, plus, X, equals
dimaraw [331]

Answer:

5a  

2

+4ab+5b  

2

Step-by-step explanation:

step  1. (((0-(4•(a2)))+3ab)+(12•(b2)))+(((9•(a2))+ab)-7b2)

 step 2. (((0-(4•(a2)))+3ab)+(12•(b2)))+((32a2+ab)-7b2)

step 3.(((0-(4•(a2)))+3ab)+(22•3b2))+(9a2+ab-7b2)

step 4. (((0-(4•(a2)))+3ab)+(22•3b2))+(9a2+ab-7b2)

step 5. 5.1    Factoring    5a2 + 4ab + 5b2

6 0
3 years ago
-3(-4b - 7n) use n = 8 and b = 2
gogolik [260]

The answer for your problem is 192

7 0
3 years ago
Which number is a solution of a² +4= 6a – 1?<br> 07<br> 6<br> 7<br> 8
LuckyWell [14K]

Answer:

a=1 or a=5

Step-by-step explanation:

a^{2}+4=6a−1

Step 1: Subtract 6a-1 from both sides.

a^{2}+4−(6a−1)=6a−1−(6a−1)

a^{2}−6a+5=0

Step 2: Factor left side of equation.

(a−1)(a−5)=0

Step 3: Set factors equal to 0.

a−1=0 or a−5=0

a=1 or a=5

(is it helpful rate me according to that

Thank You:-)

6 0
3 years ago
A store sells 2 printers for every 5 computers. The store sells 40 computers. How many printers does the store sell? I also have
Alona [7]
Well the answer of how many printers does the store sell is 16
so it would be 2 8 16

5 0
2 years ago
Read 2 more answers
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