The GCSE Computing MOOC (created with Cambridge University Press and Raspberry Pi) can be used either as a course or a flexible teaching resource,
Look up on google a software that can do it for you. Doing it through a pre-made software is about the only way to do it most computers won't allow you to.
Answer:
<u><em>DEAR HERE IS YOUR ANSWER:</em></u>
<u><em>T</em></u>he Patch Tool is part of the healing brush set of tools. These are the go-to tools for retouching and repairing your images. The Patch Tool is primarily used to repair larger areas of an image, or get rid of any distractions or blemishes.
- The patch tool was introduced into Photoshop at the same time as the Healing Brush
- You don’t have to use the Patch tool to define a selection. You can use any selection tool and then select the Patch tool. <em><u> </u></em>
<em><u>HOW TO USE PATCH TOOL IN PHOTOSHOP:</u></em>
- Click and hold the Healing Brush tool to select the Patch tool; on the Options bar, select the Destination radio button
- With the Patch tool still selected, drag to create a marquee around the source you want to use as the patch
- After you create the marquee, drag the selected source area to the destination to be repaired.
<em><u>I HOPE IT WILL WORK DEAR THANKS FOR ASKING QUESTION</u></em>
Explanation:
The answer is;
Current
Voltage
Power/Wattage
Circuit
Water moving through pipes is like electricity flowing in a circuit. The flow of electricity is an actual flow of electrons. That movement of electrons is what is known as current. Think of current as the volume of water flowing through a water pipe. The electrons need some force or pressure to move, and so is water in a pipe. The voltage is that electromotive force; the pressure that pushes the electrons in a system. The power measured in Watts is the rate at which the energy is consumed. For the current to flow the circuit must be complete. Otherwise we cannot say that we have power if the circuit is not closed.
Answer:
a=4 , b=1
Explanation:
I'm not a computer science major at all but I think I can help you with this code.
Our program wants us to add 2 to a get new a value while also subtracting 1 from b value to obtain new b value. We we want to for for as long b is not 0 and a/b is nonnegative.
One round we get:
New a=0+2=2
New b=3-1=2
Let's see if we can go another round:
New a=2+2=4
New b=2-1=1
We can't go another round because b would be negative while a is positive which would make a/b negative. So our loop stops at this 2nd round.
a=4 , b=1
Other notes:
2nd choice makes no sense because a is always going to increase because of the addition on a and b was going to decrease because of the subtraction on it.
Third choice makes no sense because a/b doesn't even exist.
Fourth choice a/b is negative not nonnegative.
