Answer:
- common = []
- num1 = 8
- num2 = 24
- for i in range(1, num1 + 1):
- if(num1 % i == 0 and num2 % i == 0):
- common.append(i)
- print(common)
Explanation:
The solution is written in Python 3.
Firstly create a common list to hold a list of the common factor between 8 and 24 (Line 1).
Create two variables num1, and num2 and set 8 and 24 as their values, respectively (Line 3 - 4).
Create a for loop to traverse through the number from 1 to 8 and use modulus operator to check if num1 and num2 are divisible by current i value. If so the remainder of both num1%i and num2%i will be zero and the if block will run to append the current i value to common list (Line 6-8).
After the loop, print the common list and we shall get [1, 2, 4, 8]
This seems more of a statement then a question if theres more id like to help
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Answer:
In opp friend function is a function that gives the same access to private and protected data. It is declared in class that is granting access.
Explanation:
#include<iostream.h>
using namespace std;
class Sum
{
int a, b, add;
public:
void input()
{
cout << "Enter the value of l and m:";
cin >> l>>m; taking input from users
}
friend void add(sum &t);
void display()
{
cout << "The sum is :" << z;
}
};
void add(sum & p)
{
p.add = p.a + p.b;
}
int main()
{
sum p1;
p1.input();
add(p1);
p1.display();
return false;
if(display==5)
{
return true; //true is returned if sum is equal to 5
}
else //if they are not the same
{
return false;
}
}
