What is the problem I can’t see it sorry
Since:
ax(2x + y - 5) = 6x^2 +3xy - 15x,
we should factor X out of the second equation to find out the value of a:
6x^2 + 3xy - 15x =
x(6x + 3y - 15),
Now that we factored X out, to find a, we need to find the other common factor:
(6x + 3y - 15) / (2x + y - 5),
which is 3.
Hence the value of a is 3
The numbers are: 36 and 11 .
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Explanation:
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Let us represent the TWO (2) numbers with the variables;
"x" and "y" .
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x + y = 47 .
y − x = 25.
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Since: " y − x = 25 " ;
Solve for "y" in terms of "x" ;
y − x = 25 ;
Add "x" to each side of the equation:
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y − x + x = 25 + x ;
to get:
y = 25 + x .
Now, since:
x + y = 47 ;
Plug in "(25 + x)" as a substitution for "y"; to solve for "x" :
x + (25 + x) = 47 ;
x + 25 + x + 47 ;
2x + 25 = 47 ;
Subtract "25" from each side of the equation:
2x + 25 − 25 = 47 − 25 ;
2x = 22 ;
Divide EACH SIDE of the equation by "2" ;
to isolate "x" on one side of the equation; and to solve for "x" ;
2x / 2 = 22 / 2 ;
x = 11 ;
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x + y = 47<span> ;
</span>Plug in "11" for "x" into the equation ; to solve for "y" ;
11 + y = 47 ;
Subtract "11" from EACH SIDE of the equation;
to isolate "y" on one side of the equation; and to solve for "y" ;
11 + y − 11 = 47 − 11 ;
y = 36 .
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So: x = 11 , y = 36 ;
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Let us check our work:
y − x = 25 ;
36 − 11 =? 25 ? Yes!
x + y = 47 ;
36 + 11 =? 47 ? Yes!
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The numbers are: 36 and 11 .
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Answer:
number of tape sides = 2.1667 tape sides
Explanation:
We know that each song took 1/6 of a side of tape to be recorded.
To know how many tape sides were used to record 13 songs, all we have to do is cross multiplication as follows:
1 song ..................> 1/6 of a tape side
13 songs ..............> ?? tape sides
Number of tape sides = [(13) * (1/6)] / 1
number of tape sides = 2.1667 tape sides
Hope this helps :)
