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1 year ago

What is 9 divided by 2113

Mathematics

2 answers:

zepelin [54]1 year ago

8 0

That is the answer= 0.00425934

Pepsi [2]1 year ago

7 0

9 divided by 2113 is

0.0042593469

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The slope of the line below is -2. Use the coordinates of the labeled point to

Vilka [71]

Answer:

We can express the equation for any linear equation with slope -2 and point (x0,y0) as:

$y=-2x+(y_0+2x_0)\\\\y-y_0=-2(x-x_0)$

Step-by-step explanation:

Incomplete question:

There is no point to complete the equation.

As we have no point to complete the linear equation, we will solve for any given point (x0,y0) and a slope of m=-2.

The linear equation can be written generically as:

$y(x)=mx+b\\\\y(x)=-2x+b$

If a point, like (x0,y0) belongs to the linear equation, it satisfies its equation. Then:

$y_0=-2x_0+b$

Then, we can calculate b as:

$y_0=-2x_0+b\\\\b=y_0+2x_0$

We can express the equation for any linear equation with slope -2 and point (x0,y0) as:

$y=-2x+(y_0+2x_0)\\\\y-y_0=-2(x-x_0)$

6 0

3 years ago

1900 people attended a baseball game. 1691 of the people attending supported the home team while, 209 supported the visiting tea

Andrew [12]

The answer to the percentage of home team fans in attendance is 89%

6 0

3 years ago

As Sales Manager for ISeeYou Productions, you are planning to review the prices you charge clients for television advertisement

aksik [14]

The development fee p can be modeled by the equation p=-400q+9600 where p is the price the company charges and q is the number of contracts they get. The total revenue R ISeeYou obtains by signing q contracts is found by using the function: $R(q)=-400q^{2}+9600q$ . The cost ISeeYou Productions can be found by using the following function: C(q)=800q+16000. The monthlhy profit of Express ISeeYou Productions if found with the next function: $P(q)=-400p^{2}+8800q-16000$ . ISeeYou should sign 2 or 20 contracts to break even.

a) In order to solve part a of the problem, we will suppose the price will have a linear relation with the amount of contracts they signed, so we need to find two points to build this function.

We know that when signing 6 contracts, the company charges $7,200, so our first point will be:

(6, 7200)

we also know that the company signs 14 contracts when they charge $4,000. So our second point is:

(14, 4000)

so we can use these points to find the slope of the line by using the

slope formula:

$m=\frac{p_{2}-p_{1}}{q_{2}-q_{1}}$

$m=\frac{4000-7200}{14-6}$

so the slope is:

m=-400

We can now use one of those points and the slope to find the function for the price, so we get:

$y-y_{1}=m(x-x_{1})$

$p-p_{1}=m(q-q_{1})$

if we used the point: (6, 7200) we get:

$p-7200=-400(q-6)$

which can now be simplified:

p=-400q+2400+7200

so the price function is:

p=-400q+9600

b) In order to find the revenue equation we need to multiply the price equation by the amount of contracts they signed in a month, so we get:

R(q)=pq

$R(q)=(-400q+9600)q$

$R(q)=-400q^{2}+9600q$

c) The cost can be found by adding the fixed cost and the variable cost, so we get:

C(q)=800q+16000

d) The profit is found by subtracting the montly cost from the monthly revenue, so we get:

P(q)=R(q)-C(q)

$P(q)=-400q^{2}+9600q-(800q+16000)$

so we can now simplify our function to get:

$P(q)=-400q^{2}+9600q-800q-16000$

$P(q)=-400q^{2}+8800q-16000$

e) In order to find the number of contracts for the company to break even, we need to find the q contracts that will give a profit of $0 so we set the function of the previous part of the problem equal to zero so we get:

$P(q)=-400q^{2}+8800q-16000$

$-400q^{2}+8800q-16000=0$

we can start by factoring a -400 from the left side so we get:

$-400(q^{2}-22q+40)=0$

we can divide both sides of the equation into -400 to simplify the equation so we get:

$q^{2}-22q+40=0$

and now we can factor the left side of the equation to get:

(q-20)(q-2)=0

we can now split this into two equations to get:

q-2=0 and q-20=0

so our two answers are:

q=2 and q=20

the company will break even when signing 2 and 20 contracts.

In the attached picture you will be able to see the break even points on the graph of revenue and cost.

For more information on how to solve this type of problems, you can go to the next link.

brainly.com/question/23407629?referrer=searchResults

6 0

2 years ago

1. Which point on the axis satisfies the inequality y

grigory [225]

Answer:

1) Point $(1,0)$ -----> see the attached figure N $1$

2) The value of x is $4$

3) I quadrant

4) $(1,1)$

5) $y>-5x+3$

Step-by-step explanation:

Part 1)

we know that

If the point satisfy the inequality

then

the point must be included in the shaded area

The point $(1,0)$ is included in the shaded area

Part 2)

we have

$x-2y\geq 4$

see the attached figure N $2$

we know that

The value for x on the boundary line and the x axis is equal to the x-intercept of the line $x-2y= 4$

For $y=0$

Find the value of x

$x-2(0)= 4$

$x=4$

The solution is $x=4$

Part 3)

we have

$x\geq 0$ -----> inequality A

The solution of the inequality A is in the first and fourth quadrant

$y\geq 0$ -----> inequality B

The solution of the inequality B is in the first and second quadrant

the solution of the inequality A and the inequality B is the first quadrant

Part 4) Which ordered pair is a solution of the inequality?

we have

$y\geq 4x-5$

we know that

If a ordered pair is a solution of the inequality

then

the ordered pair must be satisfy the inequality

we're going to verify all the cases

case A) point $(3,4)$

Substitute the value of x and y in the inequality

$x=3,y=4$

$4\geq 4(3)-5$

$4\geq 7$ ------> is not true

therefore

the point $(3,4)$ is not a solution of the inequality

case B) point $(2,1)$

Substitute the value of x and y in the inequality

$x=2,y=1$

$1\geq 4(2)-5$

$1\geq 3$ ------> is not true

therefore

the point $(2,1)$ is not a solution of the inequality

case C) point $(3,0)$

Substitute the value of x and y in the inequality

$x=3,y=0$

$0\geq 4(3)-5$

$0\geq 7$ ------> is not true

therefore

the point $(3,0)$ is not a solution of the inequality

case D) point $(1,1)$

Substitute the value of x and y in the inequality

$x=1,y=1$

$1\geq 4(1)-5$

$1\geq -1$ ------> is true

therefore

the point $(1,1)$ is a solution of the inequality

Part 5) Write an inequality to match the graph

we know that

The equation of the line has a negative slope

The y-intercept is the point $(3,0)$

The x-intercept is a positive number

The solution is the shaded area above the dashed line

the equation of the line is $y=-5x+3$

The inequality is $y>-5x+3$

3 0

3 years ago

Read 2 more answers

What is the distance in units from (2, -12) to (-11, -12) 20 POINTSSS HURRY PLEASEEEE

sweet [91]

Answer:

d= (-11-2)^2 + (-12--12)^2

d= (-13)^2 + (0)^2

d=169

square root the 169

answer is 13

that's the distance from (2, -12) (-11, -12)

hope that helps

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers