Since the slope is -2 we know that m=-2. Now use the standard form of y=mx+b and plug in the coordinates (-8,2). We know y=2, x=-8, and m=-2. Therefore we get 2=-2(-8)+b. Now solve for b and you get -14. Therefore, the equation is y=-2x-14.
Hope this helped!
Recall the sum identity for cosine:
cos(a + b) = cos(a) cos(b) - sin(a) sin(b)
so that
cos(a + b) = 12/13 cos(a) - 8/17 sin(b)
Since both a and b terminate in the first quadrant, we know that both cos(a) and sin(b) are positive. Then using the Pythagorean identity,
cos²(a) + sin²(a) = 1 ⇒ cos(a) = √(1 - sin²(a)) = 15/17
cos²(b) + sin²(b) = 1 ⇒ sin(b) = √(1 - cos²(b)) = 5/13
Then
cos(a + b) = 12/13 • 15/17 - 8/17 • 5/13 = 140/221
Answer:
y= -3/5x - 7 (assuming slope-intercept form)
Step-by-step explanation:
First, we see the slope. The basic template for a slope-intercept question is
y=mx + b
So, we put in -3/5 as "m" in this case, as it is the slope to get y= -3/5x +b
To find b, we can just try out the point that the equation gave us.
-3/5 * -5 = 3
Then, to get to -4 from 3, we need to subtract 7.
Then, we get our whole slope-intercept equation. y=-3/5x - 7
The wording of your question suggests that there were answer choices. Mind sharing them?
The system <span>y=-2x^2 y=x-2 would be best written as:
</span><span>y=-2x^2
y=x-2 If you subst. x-2 for y in the first equation, you'll get:
x-2 = -2x^2, or 2x^2 + x - 2 = 0.
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