The 3rd and 5th systems of equations are the answer.
Point A is at (3,-1), so all you do is input 3 for x and -1 for y into all the equations. For the systems to work, both equations must work with (3,-1).
Only the third and fifth boxes work.
Step-by-step explanation:
7×9÷2
By using the rule of BODMAS , we get
7×9÷2
7×4.5
31.5
Answer:
Step-by-step explanation:
a1 = - 2
an = a1 * r^(n - 1)
a6 = -486
-486 = - 2 * r^(6-1) Divide by 2
243 = r^5
The largest value that r could be is 3.
4^5 = 1024
(243)^(1/5) = 3
So the general formula
an = -2*(3)^(n - 1)
I'm pretty sure it's the square. The square can be divided into 4 equal parts, each part able to reflect each other.
Answer: approximately 49 feets
Step-by-step explanation:
The diagram of the tree is shown in the attached photo. The tree fell with its tip forming an angle of 36 degrees with the ground. It forms a right angle triangle,ABC. Angle C is gotten by subtracting the sum of angle A and angle B from 180(sum of angles in a triangle is 180 degrees).
To determine the height of the tree, we will apply trigonometric ratio
Tan # = opposite/ adjacent
Where # = 36 degrees
Opposite = x feets
Adjacent = 25 feets
Tan 36 = x/25
x = 25tan36
x = 25 × 0.7265
x = 18.1625
Height of the tree from the ground to the point where it broke = x = 18.1625 meters.
The entire height of the tree would be the the length of the fallen side of the tree, y + 18.1625m
To get y, we will use Pythagoras theorem
y^2 = 25^2 + 18.1625^2
y^2 = 625 + 329.88
y^2 = 954.88
y = √954.88 = 30.9 meters
Height of the tree before falling was
18.1625+30.9 = 49.0625
The height of the tree was approximately 49 feets