By using pythagoras theorem where
(Base)^2 +(perpedicular)^2 = (hypotenuse)^2
So,
(5)^2 +(12)^2 = (hypotenuse)^2
25 + 144 = (hypotenuse)^2
169 = (hypotenuse)^2
13 = hypotenuse
So, hypotenuse = 13
Answer:
Step-by-step explanation:
If Point C <em>was </em>located between A & B, then:
However, we are told Point C is <em>not</em>; therefore:
<span>The prime factorisation for 525 in expanded form could be calculated as follows: 5 into 525 = 105 5 into 105 = 21 21 = 3 x 7</span>
Area = lxb
=(5x - 4) x (2x - 5)
=10x*2 - 25x - 8x + 20
=10x*2 -33x +20
so b is correct option and give me brainliest
