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2 years ago

Please help............

Mathematics

1 answer:

Wittaler [7]2 years ago

3 0

Answer:

the right answer is reflection across l2

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Ryan has nine 14 ounce bags of popcorn to repackage and sell at the school fair. a small bag holds 3 ounces. how many small bags

Mice21 [21]

14 divided by 3 you would get 4 2/3 but since all the bags have to have the same amount it should be 4

Hope this helps!

3 0

3 years ago

Solve for x:<br> 4x – 7 = 8x + 33

Lera25 [3.4K]

Answer:

x = 10

Step-by-step explanation:

Hey there!

To solve this question we will use PEMDAS (order of operations)

4x−7=8x+33

Subtract 8x from both sides.

4x−7−8x=33

Combine 4x and −8x to get −4x.

−4x−7=33

Add 7 to both sides.

−4x=33+7

Add 33 and 7 to get 40.

−4x=40

Divide both sides by −4.

x= 40/-4

Divide 40 by −4 to get −10.

x=−10

6 0

1 year ago

Is 0.12112112112 a rational number?

slega [8]

Answer: Yes

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Circumference of the circle

Alja [10]

Answer:

37 5/7

Step-by-step explanation:

use formular it will be 2pie -22/7 ×radius

since we have been given only radius it will be

2×22/7×6=37 5/7

8 0

2 years ago

Read 2 more answers

Q6. (15 points) IQ examination scores of 500 members of a club are normally distributed with mean of 165 and SD of 15.

melamori03 [73]

Answer:

a) 0.8413

b) 421

c) $P_{95} = 189.675$

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 165

Standard Deviation, σ = 15

We are given that the distribution of IQ examination scores is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(IQ scores at most 180)

P(x < 180)

$P( x < 180) = P( z < \displaystyle\frac{180 - 165}{15}) = P(z < 1)$

Calculation the value from standard normal z table, we have,

$P(x < 180) = 0.8413 = 84.13\%$

b) Number of the members of the club have IQ scores at most 180

n = 500

$\text{Members} = n\times \text{P(IQ scores at most 180)}\\= 500\times 0.8413\\=420.65 \approc 421$

c) P(X< x) = 0.95

We have to find the value of x such that the probability is 0.95

$P( X < x) = P( z < \displaystyle\frac{x - 165}{15})=0.95$

Calculation the value from standard normal z table, we have,

$P(z < 1.645) = 0.95$

$\displaystyle\frac{x - 165}{15} = 1.645\\\\x = 189.675$

$P_{95} = 189.675$

8 0

3 years ago