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n200080 [17]
3 years ago
8

Find the x-intercept and the y-intercept x - 2y = 6​

Mathematics
1 answer:
Reptile [31]3 years ago
7 0

Answer:

x-intercept = 6; y-intercept = 3

Step-by-step explanation:

To find the x-intercept, set y as 0 and solve for x.

To find the y-intercept, set x as 0 and solve for y.

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Find the nth term<br><br> 1, 5, 9. 13, 17
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a1 = 1 and d = 4

a(n) = a1 + d(n - 1)

a(n) = 1  + 4(n - 1)

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2,99,790,000 in scientific notation
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So we have 299790000, we want to have only one digit in front of the decimal, 2.9979x10^9

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Comppete the equation <br> X^2+y^2-10x+6y=15
mart [117]
I believe you meant:  Use completing the square to determine the center and radius of the circle represented by this equation:   <span>X^2+y^2-10x+6y=15

x^2 - 10x + 25 - 25 + y^2 + 6y + 9 - 9 = 15
Then:
     (x-5)^2               +   (y+3)^2            = 24   = 2sqrt(6)

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3 years ago
PLEASE HELP ASAP. WILL GIVE BRAINLIEST ANSWER.
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Step-by-step explanation:

6 0
2 years ago
one-third of the people from country A claim that they are from country B, and the rest admit they are from country A. One-fourt
In-s [12.5K]

Answer: 3 : 2

Step-by-step explanation:

Let A represents the total population of country A and B represents the total population of country B.

According to the question,

 \text{The population of country A that admit they are from B} = \frac{1}{3}\text{ of }A

⇒ \text{ The population of A that admit they are from country A }= A - \frac{1}{3} \text{ of } A

= \frac{3-1}{3} A

= \frac{2}{3} A

\text{The population of country B that admit they are from A} = \frac{1}{4}\text{ of }B

⇒ \text{ The total population that claims that they are from A }= \frac{2}{3} A +\frac{1}{4} B

But, Again according to the question,

The total population that claims that they are from A =  one half of the total population of A and B.

⇒ \frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}(A+B)

⇒ \frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}A+\frac{1}{2}B

⇒ \frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}A+\frac{1}{2}B

⇒ \frac{2}{3} A - \frac{1}{2}A= \frac{1}{2}B-\frac{1}{4} B

⇒ \frac{4}{6} A - \frac{3}{6}A= \frac{2}{4}B-\frac{1}{4} B

⇒ \frac{1}{6} A = \frac{1}{4} B

⇒ A =\frac{6}{4}B

⇒ \frac{A}{B} =\frac{3}{2}

8 0
3 years ago
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