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Inga [223]
3 years ago
8

Which system of inequalities is represented by the graph?

Mathematics
2 answers:
Tomtit [17]3 years ago
6 0

Answer:

y\leq -1 \text{ and }y are system of inequalities is represented by the graph.

Step-by-step explanation:

We are given four option and need to choose correct inequality for given graph.

In graph, we can see two line

Red line: It is horizontal solid line passing through (0,-1) and shaded region above the line.

Equation of line: y≥-1

Blue line: It is slant dotted line passing through origin and (-2,1)

Equation of line: y

System of inequalities represented by the graph.

y\leq -1 \text{ and }y

Thus, y\leq -1 \text{ and }y are system of inequalities is represented by the graph.

mixer [17]3 years ago
5 0

on ed is C) y < –x  

y ≥ –1

just took the test

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Step-by-step explanation:

f(t) =  -2t + 3

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f(-2) = -4 + 3

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3 years ago
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Miranda has a bag of marbles with 5 blue marbles, 1 white marbles, and 1 red marbles. Find the following probabilities of Mirand
kvasek [131]

Answer:

(a)\frac{5}{7},\frac{1}{6} (b)\frac{1}{7},\frac{1}{6} (c)\frac{5}{7},\frac{2}{3},\frac{3}{5}

Step-by-step explanation:

GIVEN: Miranda has a bag of marbles with 5 blue marbles, 1 white marbles, and

TO FIND: a) A Blue, then a red Preview

,b)A red, then a white Preview

,c) A Blue, then a Blue, then a Blue.

SOLUTION:

Total marbles in bag =7

(a)

Probability of drawing blue marble =\frac{\text{total blue marble}}{\text{total marbles}}

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As marble is not returned to bag,

Probability of drawing red marble  =\frac{\text{total red marble}}{\text{total marbles}}

                                                         =\frac{1}{6}

(b)

Probability of drawing red marble =\frac{\text{total red marble}}{\text{total marbles}}

                                                          =\frac{1}{7}

As marble is not returned to bag,

Probability of drawing white marble  =\frac{\text{total white marble}}{\text{total marbles}}

                                                         =\frac{1}{6}

(c)

Probability of drawing blue marble =\frac{\text{total blue marble}}{\text{total marbles}}

                                                          =\frac{5}{7}

As marble is not returned to bag,

Probability of drawing second blue marble  =\frac{\text{total blue marble}}{\text{total marbles}}

                                                                         =\frac{4}{6}=\frac{2}{3}

As marble is not returned to the bag

Probability of drawing third blue marble   =\frac{\text{total blue marble}}{\text{total marbles}}

                                                                    =\frac{3}{5}

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Answer:

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