Triangle PQR is transformed to triangle P'Q'R'. Triangle PQR has vertices P(3, −6), Q(0, 9), and R(−3, 0). Triangle P'Q'R' has v
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The length 2.3 and 7.8 units
We have given that ΔABC, c = 5. 4, a = 3. 3, and measure of angle A = 20 degrees.
<h3>What is the formula for low of cosine?</h3>The Law of Cosines, which tells us
giving us a quadratic equation for b we can solve. But let's do it with the Law of Sines as asked.
We have c,a,A so the Law of Sines gives us sin C
There are two possible triangle angles with this sine, supplementary angles, one acute, one obtuse
Both of these make a valid triangle with A=20°. They give respective B's:
So we get two possibilities for b:
2.3 units and 7.8 units
Therefore we get the length 2.3 and 7.8 units
To learn more about the low of sine and cosine visit:
Answer: 2.3 units and 7.8 units
Let's check it with the Law of Cosines:
There's a shortcut for the quadratic formula when the middle term is 'even.'
Looks good.