Question

6i4+6i3−2i2+−49−−−−√ rewritten in a+bi form

Answer 1

Answer:

$8+i$

Step-by-step explanation:

We are given that an expression

$6i^4+6i^3-2i^2+\sqrt{-49}$

We have to rewrite in the form of a+bi

$6(i^2)^2+6i^3-2i^2+\sqrt{-49}$

We know that

$i^2=-1$

$i^3=-i$

$\sqrt{-1}=i$

Using the identity

Then, we get

$6-6i-2(-1)+7i$

$(6+2)+(7-6)i$

$8+i$

This is required form of a+ib