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3 years ago

The population of a bacteria colony increased by p% each day for 4 days in a row.

Mathematics

1 answer:

iren [92.7K]3 years ago

6 0

Answer:

Step-by-step explanation:

(1+p)^4 = 5.0625

1+p = 5.0625^0.25 = 1.5

p = 0.5

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4 years ago

Pls help! evaluate f(4) on this table

Kruka [31]

Answer:

Step-by-step explanation:

f(4) just means use 4 for x. The table has all the x's across the top (sometimes they are in columns instead) The f(x) in the second row is the output that goes with each x. When x is 4, the f(x) is 37.

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3 years ago

Please help me ASAP!Please this is due soon and i don't have all day.

Helga [31]

Answer:

Section 1: 5.59%

Section 2: -2.16%

Section 3: -10.82%

Section 4: -6.54%

Section 5: -2.16%

Section 6: 7.86%

Explanation:

The formula to calculate the percent change in mass is given as:

$PercentChange = \frac{ChangeInMass}{StartingMass}*100=\frac{NewMass - OldMass}{OldMass}*100$

1- Section 1:

Old mass = 7.83 g and New mass = 8.268 g

$PercentChange = \frac{8.268-7.83}{7.83}*100 =$ 5.59%

2- Section 2:

Old mass = 7.4 g and New mass = 7.24 g

$PercentChange = \frac{7.24-7.4}{7.4}*100 =$ -2.16%

3- Section 3:

Old mass = 7.3 g and New mass = 6.51 g

$PercentChange = \frac{6.51-7.3}{7.3}*100 =$ -10.82%

4- Section 4:

Old mass = 7.49 g and New mass = 7.0 g

$PercentChange = \frac{7.0-7.49}{7.49}*100 =$ -6.54%

5- Section 5:

Old mass = 7.4 g and New mass = 7.24 g

$PercentChange = \frac{7.24-7.4}{7.7.4}*100 =$ -2.16%

6- Section 6:

Old mass = 7.89 g and New mass = 8.51 g

$PercentChange = \frac{8.51-7.89}{7.89}*100 =$ 7.86%

Hope this helps :)

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3 years ago