Answer:
the interquartile range is 13.5
minimum 16
maximum 43
medium 29
lower Q1 24
upper Q3 37.5 or 38
Range 27
The vertical asymptote of f(x) is (A) x = 0, –9.
<h3>
What is a function?</h3>
- A function is an expression, rule, or law in mathematics that describes a relationship between one variable (the independent variable) and another variable (the dependent variable).
- Functions are common in mathematics and are required for the formulation of physical relationships in the sciences.
To find the vertical asymptote of f(x):
The vertical asymptotes of a function are the zeroes of the denominator of a rational function
The function is given as:
Set the denominator to 0:
Factor out x:
Express 81 as 9^2:
Express the difference between the two squares:
Split, or or .
Solve for x:
Therefore, the vertical asymptote of f(x) is (A) x = 0, –9.
(See attachment for the graph of f(x))
Know more about functions here:
brainly.com/question/6561461
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The complete question is given below:
Consider the function f(x)=(x-9)/(x^3-81x) . find the vertical asymptote(s) of f(x).
A) x = 0, –9
B) x = –9
C) x = 0, 9
D) x = 9
The answer is that I don’t know
Answer:
two (n = 4, and n = -1)
Step-by-step explanation:
Let's solve it as follows:
First, we can divide out the common factor of 3 from each side, to get:
n(2n-8) = 8 -2n
Next, we expand, and move all the terms over to the right hand side (so that we have 0 on the LHS - as this is how we will want to solve the quadratic equation):
2n^2 - 8n - 8 +2n = 0
2n^2 - 6n - 8 = 0.
We also see we can further simplify by dividing out the factor of 2, to get:
n^2 -3n -4. = 0
Next, as this is a quadratic, the usual next step is to factorise, to get:
(n-4)(n+1) = 0
So we see that n = 4 and n = -1 are the two solutions.