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3 years ago

What are the values for the coefficients and constant term of 0 = 2 + 3x2 – 5x?

Mathematics

2 answers:

Zielflug [23.3K]3 years ago

8 0

Answer:

a= 3 b= -5 c=2

Step-by-step explanation:

i just did it on edge

tangare [24]3 years ago

4 0

Keywords:

Polynomial, variable, coefficients, constant term.

For this case, the first thing we must do is rewrite the polynomial in a standard way. For this, we reorder the polynomial coefficients.

The standard form of the polynomial is:

$ax ^ 2 + bx + c$

Where,

a, b, c: are the coefficients of the polynomial.

x: is the variable

Rewriting the polynomial we have:

$3x ^ 2-5x + 2$

Comparing with the standard form we have that the values of the coefficients are given by:

$a = 3\\b = -5\\c = 2$

Answer:

The values for the coefficients and constant term are:

$a = 3\\b = -5\\c = 2$

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Refer to the diagram shown below.

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Find the area of the triangle with the given base and height. b = 3 m and h = 10 1/2 m

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Statement:

The base of a triangle is 3m and its height is $10 \frac{1}{2}$ m.

To find out:

The area of the triangle.

Solution:

Given, base = 3m, height = $10 \frac{1}{2}$ m
We know,

$\sf \: area \: \: of \: \: a \: \: triangle = \frac{1}{2} \times base \: \times height$

Therefore, the area of the triangle

$\sf = (\frac{1}{2} \times 3 \times 10 \frac{1}{2} ) {m}^{2} \\ \sf = ( \frac{1}{2} \times 3 \times \frac{21}{2} ) {m}^{2} \\ = \sf \frac{63}{4} {m}^{2} \\ = \sf 15\frac{3}{4} {m}^{2}$