The expected count of visits is the mean or average visits to each feeder
The expected count of visits to the third feeder is 87.5
<h3>How to determine the expected count of visit?</h3>
The table of values is given as:
Feeder 1 2 3 4
Observed visits 80 90 92 88
In this case, the null hypothesis implies that the visits to each feeder are uniformly distributed
So, the expected count is calculated using:
Expected count =Visits/Feeders
This gives
Expected count = 350/4
Evaluate the quotient
Expected count = 87.50
Hence, the expected count of visits to the third feeder is 87.5
Read more about chi square goodness of fit test at:
brainly.com/question/4543358
Evaluate 4 − 0 . 2 5 g + 0 . 5 h 4−0.25g+0.5h4, minus, 0, point, 25, g, plus, 0, point, 5, h when g = 1 0 g=10g, equals, 10 and
abruzzese [7]
Not sure about the weird echo in the question but I think we're being ask to evaluate
4 - 0.25g + 0.5h
when g=10, h=5
That's
4 - 0.25(10) + 0.5(5) = 4 - 2.5 + 2.5 = 4
Answer: 4
Answer:
x = 9/25
y = 7/25
z = 4/25
Step-by-step explanation:
2x + y = 1 .......(1)
3y + z = 1 ........(2)
x + 4z = 1 ........(3)
Elimination 1 and 2
2x + y = 1 | ×3 |
3y + z = 1 | ×1 |
6x + 3y = 3
3y + z = 1
___________--
6x - z = 2 .............. (4)
Elimination 3 and 4
x + 4z = 1 | ×6 |
6x - z = 2 | ×1 |
6x + 24z = 6
6x - z = 2
___________--
25z = 4
z = 4/25
Elimination 3 and 4
x + 4z = 1 | ×1 |
6x - z = 2 | ×4 |
x + 4z = 1
24x - 4z = 8
___________+
25x = 9
x = 9/25
Subsitution 1
2x + y = 1
2(9/25) + y = 1
18/25 + y = 1
y = 1 - 18/25
y = 25/25 - 18/25
y = 7/25
_______________________________
<span>y = 12x
Substitute 3 for x
</span><span>y = 12(3)
Multiply
Final Answer: B.) y=36</span>
