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Kay [80]
3 years ago
15

7. Represent 56 + x = 7 using subtraction. What is x? Explain your reasoning

Mathematics
2 answers:
Setler79 [48]3 years ago
6 0
56+x=7

You would be subtracting 56 from both sides, which would result in;

x=-49

This is the correct option when using subtraction as the follow through.

Hope I helped, if you need anything else let me know. :)
Pie3 years ago
5 0

Answer: 8

Step-by-step explanation: 7 X 8 = 56

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the lenght of a rectangle is 2 cm less than 7 times the width. the perimeter is 60 cm . find the width and lenght
vampirchik [111]
First, you want to establish your equations.

L=7W-2
P=60

This is what we already know. To find the width, we have to plug in what we know into P=2(L+W), our equation to find perimeter.

60=2(7W-2+W)

Now that we only have 1 variable, we can solve.

First, distribute the 2.
60=14W-4+2W

Next, combine like terms.

60=16W-4

Then, add four to both sides.

64=16W

Lastly, divide both sides by 16


W=4

To find the length, we plug in our width.

7W-2

7(4)-2

28-2

L=26
8 0
3 years ago
Which expressions are equivalent to z+(z+6)
Nezavi [6.7K]

Answer:

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Subtract and simplify 20 2/7 - 26/35
marissa [1.9K]
20& 10/35 - 26/35 

19& 16/35 simplified to it's fullest.
4 0
4 years ago
6x - 2y = 5
laiz [17]

Answer:

The given system has NO SOLUTION.

Step-by-step explanation:

Here, the given system of equation is:

6 x -  2 y = 5     .......... (1)

3 x  - y = 10          .... (2)

Multiply equation 2 with (-2), we get:

3 x  - y = 10     ( x -2)

⇒  - 6 x + 2 y = - 20

Now, ADD this to equation (1) , we get:

6 x - 2 y  - 6 x + 2 y  = 5 - 20

or, 0 = - 15

WHICH IS NOT POSSIBLE as 0 ≠ -15

Hence, the given system has NO SOLUTION.

7 0
3 years ago
Estimate the solution to the system of equations. asap, please!! I will mark for brain list
Darya [45]

Answer:

(1 \frac{1}{3}, 2 \frac{1}{3} )

Step-by-step explanation:

Given the 2 equations

7x - y = 7 → (1)

x + 2y = 6 → (2)

Multiplying (1) by 2 and adding to (2) will eliminate the y- term

14x - 2y = 14 → (3)

Add (2) and (3) term by term to eliminate y

15x = 20 ( divide both sides by 15 )

x = \frac{20}{15} = \frac{4}{3} = 1 \frac{1}{3}

Substitute this value of x into either of the 2 equations and solve for y

Substituting in (2)

\frac{4}{3} + 2y = 6

2y = 6 - \frac{4}{3} = \frac{14}{3} ( divide both sides by 2 )

y = \frac{7}{3} = 2 \frac{1}{3}

7 0
3 years ago
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