All categories

3 years ago

Find the perimeter of the square on the centimeter grid

Mathematics

1 answer:

olga_2 [115]3 years ago

7 0

16 ... i hope its right

You might be interested in

You tell your mom that you want ₹700₹700₹, 700 as pocket money every month. She can deposit some money in the bank such that the

Colt1911 [192]

Let me think? I’m not sure

6 0

4 years ago

(30 points!) Powers of i worksheet

Gelneren [198K]

Answer:

x+7=14

x=7

(7)+7=14

Step-by-step explanation:

7 0

3 years ago

Find the angle between the vectors. (First find an exact expression and then approximate to the nearest degree.)

Luda [366]

Answer:

$a.b = (1*0) + (-4*2) +(1*-2)= -10$

And replacing we got:

$cos \theta = \frac{-10}{\sqrt{18} \sqrt{8}}= -\frac{10}{\sqrt{144}}= -\frac{10}{12}= -\frac{5}{6}$

And we can find the angle with the inverse cosine function and we got:

$\theta =cos^{-1} (-\frac{5}{6})= 146.44°$

Step-by-step explanation:

for this case we can use the following identity:

$cos \theta = \frac{a.b}{|a| |b|}$

We can begin finding the norm for each vector and we got:

$|a| =\sqrt{(1)^2 +(-4)^2 +(1)^2}= \sqrt{18}$

$|b| =\sqrt{(0)^2 +(2)^2 +(-2)^2}= \sqrt{8}$

Now we can find the dot product and we got:

$a.b = (1*0) + (-4*2) +(1*-2)= -10$

And replacing we got:

$cos \theta = \frac{-10}{\sqrt{18} \sqrt{8}}= -\frac{10}{\sqrt{144}}= -\frac{10}{12}= -\frac{5}{6}$

And we can find the angle with the inverse cosine function and we got:

$\theta =cos^{-1} (-\frac{5}{6})= 146.44°$

5 0

3 years ago

Tanya wants to order 50 pizzas for a party. However, the pizza supplier can deliver only 45 pizzas on the given date. How will y

olga nikolaevna [1]

Answer:

Step-by-step explanation:

The demand is 50 and the supply is 45. Since 50 > 45 the answer is that the demand is greater than the supply.

3 0

3 years ago

Can I get the ans for this qs of maths?

grigory [225]

Answer:

2880 m

Step-by-step explanation:

find the area under the graph. i have split it into 3 areas A, B and C

A (trapezium) = 1/2 x (150 + 160) x 15 = 2325

B (trapezium) = 1/2 x (15 + 6 ) x (160 - 110) = 525

C (triangle) = 1/2 x 10 x 6 = 30

total = 2325 + 525 + 30 = 2880

6 0

3 years ago

Find the perimeter of the square on the centimeter grid​

Find the perimeter of the square on the centimeter grid