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2 years ago

Can I get the ans for this qs of maths?

Mathematics

1 answer:

grigory [225]2 years ago

6 0

Answer:

2880 m

Step-by-step explanation:

find the area under the graph. i have split it into 3 areas A, B and C

A (trapezium) = 1/2 x (150 + 160) x 15 = 2325

B (trapezium) = 1/2 x (15 + 6 ) x (160 - 110) = 525

C (triangle) = 1/2 x 10 x 6 = 30

total = 2325 + 525 + 30 = 2880

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in the bag, there are certain number of toy- blocks with alphabets A,B,C and D written on them. The ratio of blocks A:B:C:D is 4

Svet_ta [14]

Given, the ratio of blocks A, B, C,D are in the ratio 4:7:3:1

Let us consider the common ratio to be ‘x’.

So, toy blocks with alphabet A is 4x and

toy blocks with alphabet B is 7x and

toy blocks with alphabet C is 3x and

toy blocks with alphabet D is x

Again, the number of ‘A’ blocks is 50 more than the number of ‘C’ blocks.

As no. of ‘A’ and ‘C’ blocks are 4x and 3x respectively.

So,

4x=50 + 3x

x=50

Thus, the number of ‘B’ blocks is 7x = 7(50) = 350

350 is the required number.

7 0

3 years ago

Read 2 more answers

Pls help me I’ll give brainliest pls dont answer if you don’t know

Delvig [45]

Answer:

Species

Step-by-step explanation:

i read the passage hence is how i got my answers

3 0

3 years ago

Read 2 more answers

I keep getting this question wrong

padilas [110]

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3 0

1 year ago

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0

3 years ago

Please answer ASAP! Your help is deeply appreciated. Thank you in advance and stay safe.

Ostrovityanka [42]

Answer:

The answer is 128 sq ft. If you want proof, please ask in the comments.

Hope this helps!

7 0

2 years ago