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nataly862011 [7]
3 years ago
11

I need help with these five questions

Mathematics
1 answer:
garri49 [273]3 years ago
4 0

Q1. ans b

Q2.ans d

Q3.ansc

Q4.ans b

Q5.ansa

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Solve log x=2. A. 2 B. 20 C. 100 D. 1,000
Ber [7]

Answer:

100

Step-by-step explanation:

5 0
3 years ago
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Find the least common denominator of -7/x and -5/6x^2
Jlenok [28]
That is  6x^2

Both x and 6x^2 will divide into 6x^2
7 0
3 years ago
If y2 = x3 + 2, which statement is true? The equation is a function at all values of x. The equation is not a function. The equa
tatyana61 [14]

Answer:

The equation is not a function.

Step-by-step explanation:

We are given that

y^2=x^3+2

y=\pm\sqrt{x^3+2}

Function: It is mapping between the values of two sets A and B.

Each element of A has unique value in set B.

By definition of  function

In given function

y has no unique value for each value of x.

Substitute x=0

y=\pm \sqrt{0+2}=\pm \sqrt 2

Hence, it is not a function.

6 0
3 years ago
Find the radius of a circle with a circumference of 23.55 feet. Use 3.14 for
Oksi-84 [34.3K]

Answer:

3.75

Step-by-step explanation:

8 0
3 years ago
In a survey, the planning value for the population proportion is . How large a sample should be taken to provide a confidence in
tatuchka [14]

Answer:

n=350

Step-by-step explanation:

Notation and definitions

n random sample taken  (variable of interest)

\hat p=0.35 estimated proportion  (value assumed)

p true population proportion

Confidence =0.95 or 95% (value assumed)

Me=0.05 (value assumed)

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.35(1-0.35)}{(\frac{0.05}{1.96})^2}=349.586  

And rounded up we have that n=350

4 0
3 years ago
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