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patriot [66]
2 years ago
9

As a marketing manager, you are tasked with selecting a website to place your advertisement. The following sampled data shows th

e number of user visits per month over the last 3 three years:
Website 1: 10357, 10537, 10767, 10561, 10544, 10581, 10602, 10665, 10335, 10419, 10737, 10410, 10485, 10601, 10458, 10472, 10435, 10375, 10436, 10510, 10345, 10559, 10520, 10425, 10351, 10465, 10491, 10671, 10366, 10440, 10618, 10606, 10406, 10538, 10449, 10462
Website 2: 11067, 11029, 10888, 10789, 10914, 10663, 10787, 11140, 11042, 11074, 10868, 10853, 10900, 11088, 10991, 10928, 10959, 11126, 11033, 11114, 11150, 11155, 11027, 10900, 11015, 11123, 10953, 11181, 10855, 10731, 10971, 10770, 11070, 11122, 11018, 10903 Since the behavior of internet users can be considered a natural process, consider the number of views to follow normal distribution. In addition, please assume no autocorrelation or time-series nature of the data. Based on the data above, provide the answers to the following question:
A. What is the average and standard deviation of viewership of each website?
B. Is viewership different between these two websites? If yes, which website provides more views?
C. Suppose that your manager requires at least 12000 views per month. What is the probability of 12000 views happening on each website?
D. Which website provides more consistent view? How would you measure it?
E. Which website would you recommend for your advertisement?
Mathematics
1 answer:
olasank [31]2 years ago
5 0

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data :

Website 1 : 10357, 10537, 10767, 10561, 10544, 10581, 10602, 10665, 10335, 10419, 10737, 10410, 10485, 10601, 10458, 10472, 10435, 10375, 10436, 10510, 10345, 10559, 10520, 10425, 10351, 10465, 10491, 10671, 10366, 10440, 10618, 10606, 10406, 10538, 10449, 10462

Mean, xbar = ΣX/ n ; n = sample size = 36

Xbar = 377999 / 36 = 10499.9722

Standard deviation, s = √[(x - xbar)² / (n-1]

Using calculator :

Standard deviation (Website 1 :), s = 110.239865

Website 2 : 11067, 11029, 10888, 10789, 10914, 10663, 10787, 11140, 11042, 11074, 10868, 10853, 10900, 11088, 10991, 10928, 10959, 11126, 11033, 11114, 11150, 11155, 11027, 10900, 11015, 11123, 10953, 11181, 10855, 10731, 10971, 10770, 11070, 11122, 11018, 10903

Mean, xbar = ΣX/ n ; n = sample size = 36

Xbar = 395197 / 36 = 10977.6944

Standard deviation, s = √[(x - xbar)² / (n-1]

Using calculator :

Standard deviation (Website 2), s = 132.617995

2.)

Yes, the viewership between the two websites are different with the second website has a higher mean viewership with a mean of 10977.6944.

3.)

The probability of 12000 views per month on each website :

Probability = Mean viewership per month / required viewership

Website 1 :

P(12000) = 10499.9722 / 12000 = 0.8749

Website 2 :

P(12000) = 10977.6944 / 12000 = 0.9148

4.)

More consistent website :

We use the standard deviation value, the higher the standard deviation, the higher the variability :

Website 1 should be more consistent has it has a Lower standard deviation score, hence, should show lower variability than website 2.

5.)

Website suitable for advertisement should be one with higher viewership per month in other to reach a larger audience. Hence, website 2 should be recommended for advertisement.

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3 years ago
A marketing firm would like to test-market the name of a new energy drink targeted at 18- to 29-year-olds via social media. A st
Anon25 [30]

Answer:

(a) The probability that a randomly selected U.S. adult uses social media is 0.35.

(b) The probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c) The probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = an US adult who does not uses social media.

<em>Y</em> = an US adult between the ages 18 and 29.

<em>Z</em> = an US adult between the ages 30 and above.

The information provided is:

P (X) = 0.35

P (Z) = 0.78

P (Y ∪ X') = 0.672

(a)

Compute the probability that a randomly selected U.S. adult uses social media as follows:

P (US adult uses social media (<em>X'</em><em>)</em>) = 1 - P (US adult so not use social media)

                                                   =1-P(X)\\=1-0.35\\=0.65

Thus, the probability that a randomly selected U.S. adult uses social media is 0.35.

(b)

Compute the probability that a randomly selected U.S. adult is aged 18–29 as follows:

P (Adults between 18 - 29 (<em>Y</em>)) = 1 - P (Adults 30 or above)

                                            =1-P(Z)\\=1-0.78\\=0.22

Thus, the probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c)

Compute the probability that a randomly selected U.S. adult is 18–29 and a user of social media as follows:

P (Y ∩ X') = P (Y) + P (X') - P (Y ∪ X')

                =0.22+0.65-0.672\\=0.198

Thus, the probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

6 0
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Graph the line that has a slope of 6 and includes the point (0,4).
faust18 [17]

Answer:

The equation of the line with slope 6 and containing the point (0, 4) will be:

y = 6x+4

The graph of the line y = 6x+4 is attached below.

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given

  • The slope m = 6
  • The point (0, 4)

The y-intercept can be determined by setting x = 0 and determining the corresponding value of y.

The point (0, 4) indicates that:

at x = 0, y = 4

Thus, the y-intercept b = 4

now substituting b = 4 and m = 6 in the slope-intercept form of the line equation

y = mx+b

y = 6x+4

Thus, the equation of the line with slope 6 and containing the point (0, 4) will be:

y = 6x+4

The graph of the line y = 6x+4 is attached below.

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3 years ago
Write (-2 − 2i) + (10 − 4i) as a complex number in standard form.
romanna [79]

Answer:

8-6i

Step-by-step explanation:

complex number in standard form will be in the form of a+bi

(-2 − 2i) + (10 − 4i) , open parenthesis

-2- 2i +10 -4i, group like terms

-2+10 -2i -4i, combine like terms

8 - 6i

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Answer:

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