Please ANSWER THE ANSWER HAS TO BE A INTEGER OR A DECIMAL.

Mathematics

2 answers:

AnnyKZ [126]3 years ago

7 0

I got 4.3 hope it helps

Natali [406]3 years ago

5 0

Answer: 4.3

Step-by-step explanation: To find the range you have to subtract the highest number by the lowest number. So you'd subtract 2.6 by -1.7. And since -1.7 is already a negative number, it would get turned into a positive.

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Derek is solving the following equation. Find where he made a mistake.

Arisa [49]

Answer:

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4 0

3 years ago

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Find (a) arc length and (b) Area of a sector.

barxatty [35]

Answer:

a) 29.45 cm (2 dp)

b) 220.89 cm² (2 dp)

Step-by-step explanation:

<u>Formula</u>

$\textsf{Arc length}=r \theta$

$\textsf{Area of a sector}=\dfrac{1}{2}r^2 \theta$

$\quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle in radians)}$

<u>Calculation</u>

Given:

$\theta=\dfrac{5 \pi}{8}$
r = 15 cm

$\begin{aligned}\implies \textsf{Arc length} & =r \theta\\& = 15\left(\dfrac{5 \pi}{8}\right)\\& = \dfrac{75}{8} \pi \\& = 29.45\: \sf cm\:(2\:dp)\end{aligned}$

$\begin{aligned} \implies \textsf{Area of a sector}& =\dfrac{1}{2}r^2 \theta\\\\ & = \dfrac{1}{2}(15^2) \left(\dfrac{5 \pi}{8}\right)\\\\& = \dfrac{225}{2}\left(\dfrac{5 \pi}{8}\right)\\\\ & = \dfrac{1125}{16} \pi \\\\& = 220.89 \: \sf cm^2\:(2\:dp)\end{aligned}$