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Elden [556K]
3 years ago
15

A recipe calls for 1 part beans to 1½ parts rice. if 1½ parts of beans are used, how much rice should be used?

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
8 0
1 \text{ part beans} \longrightarrow  1\dfrac{1}{2}  \text{ parts rice}

1 \dfrac{1}{2}  \text{ part beans} \longrightarrow  1\dfrac{1}{2}  \times 1 \dfrac{1}{2}  \text{ parts rice}

1 \dfrac{1}{2}  \text{ part beans} \longrightarrow  \dfrac{3}{2}  \times \dfrac{3}{2}  \text{ parts rice}

1 \dfrac{1}{2}  \text{ part beans} \longrightarrow  \dfrac{9}{4} \text{ parts rice}

1 \dfrac{1}{2}  \text{ part beans} \longrightarrow  2\dfrac{1}{4} \text{ parts rice}
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Finger [1]

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Equation of other line passing through point (6 , - 11) and parallel to given line is  y = - 23 x + 127 .

Step-by-step explanation:

Given as :

The equation of one line

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∵ The equation of line in slope-intercept form is

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where m is the slope of line and c is y-intercept

Now, Compare given line with standard line equation

So, The slope of given line = m = - 23

Now, Again

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so, both the lines are parallel

For parallel line condition , Slope of both lines are equal

Let The slope of other line = M

So, M = m = - 23

Now, Equation of other line passing through point (6 , - 11) and slope - 23 in slope-point form

y - y_1 = M × (x -  x_1)

i.e y - ( - 11) = (- 23) × (x - 6)

Or, y + 11 = - 23 × x + 138

Or, y = - 23 x + 138- 11

i.e y = - 23 x + 127

So, The equation of other line  y = - 23 x + 127

Hence, Equation of other line passing through point (6 , - 11) and parallel to given line is  y = - 23 x + 127 . Answer

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