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3 years ago

Logan can carry 22 pounds of jars. Each jar weighs 32 ounces. How many jars can Logan carry?

Mathematics

1 answer:

Brums [2.3K]3 years ago

7 0

Answer:

11 Jars

Step-by-step explanation:

32 ounces = 2 pounds = 1 jar

So 22 divided by 2 = 11 jars

hope this helps

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For the following right triangle, find the side length x. Round your answer to the nearest hundredth.

tia_tia [17]

<h3>Answer: 6.93</h3>

Work Shown:

Use the pythagorean theorem to find x

a^2 + b^2 = c^2

x^2 + 11^2 = 13^2

x^2 + 121 = 169

x^2 = 169 - 121

x^2 = 48

x = sqrt(48)

x = 6.92820323027551

x = 6.93

5 0

3 years ago

Read 2 more answers

Alice needs to rent a car while on vacation. The rental company charges $17.95, plus 15 cents for each mile driven. If Alice onl

Readme [11.4K]

Answer:

Alice can drive 147 miles

Step-by-step explanation:

At first you subtract $17.95 from $40.

Then you are left with $22.05

Finally, you divide $22.05 by $0.15

And you get 147, so she can drive 147 miles without going over her limit.

7 0

3 years ago

What are the values of x and y

Gelneren [198K]

Unfortunately, there is no way I can find the value of X and Y because there is no question for it.

You can either find the value of X and Y in the problem or make X and Y your own value if you need to find something that is equivalent.

I hope this helped.

3 0

3 years ago

The distance between two schools,A and B is 2 km.A market is situated a third of the distance from A to B.How far is the market

bekas [8.4K]

Answer:

$\frac{4}{3}$

Step-by-step explanation:

Find distance between B and market: |B-M|=|M-B|

Distance between A and B: $|A-B| = 2$ , call this equation (1)

Distance between A and market $|A-M| = \frac{1}{3} |A-B|=\frac{2}{3}$ , call this equation (2)

Solve (1) - (2)

$|A-B-A+M| = 2-\frac{2}{3} \\|M-B|=|B-M|=\frac{4}{3}$

3 0

3 years ago

In microbiology, colony-forming units (CFUs) are used to measure the number of microorganisms present in a sample. To determine

zimovet [89]

Answer:

(a) 0.2650

(b) 0.0111

(d) 0.0006

Step-by-step explanation:

Given that:

In microbiology, colony-forming units (CFUs) are used to measure the number of microorganisms present in a sample.

Suppose that the number of CFUs that appear after incubation follows a Poisson distribution with mean μ = 15. &;

If the area of the agar plate is 75cm²;

what is the probability of observing fewer than 4 CFUs in a 25 cm² area of the plate.

We can determine the mean number of CFUs that appear on a 25cm² area of the plate as follows;

75cm²/25cm² = 3

Since;

mean μ = 15

mean number of CFUs that appear on a 25cm² = 15/3 = 5 CFUs

Thus ; the probability of observing fewer than 4 CFUs in a 25 cm² area of the plate is estimated as:

= P(X < 4)

Using the EXCEL FUNCTION ( = poisson.dist(3, 5, TRUE) )

we have ;

P(X < 4) = 0.2650

b) If you were to count the total number of CFUs in 5 plates, what is the probability you would observe more than 95 CFUs?

Given that the total number of CFUs = 5 plates; then the mean number of CFUs in 5 plates = 15×5 = 75 CFUs

The probability is therefore = P( X > 95 )

= 1 - P(X ≤ 95)

= 1 - poisson.dist(95,75,TRUE) ( by using the excel function)

= 0.0111

c) Repeat the probability calculation in part (b) but now use the normal approximation.

Let assume that the mean and the variance of the poisson distribution are equal

Then;

$X \sim N (\mu = 75 , \sigma^2 = 75)$

We are to repeated the probability calculation in part (b) from above;

So:

P( X > 95 )

use the normal approximation

From standard normal variable table:

P(Z > 2.3094)

Using normal table

P(Z > 2.3094) = 0.0105

(d) Find the difference between this value and your answer in part (b).

So;

the difference between the value in part c and part b is;

= 0.0111 - 0.0105

$= 6*10^{-4}$

= 0.0006 to four decimal places

5 0

3 years ago