Answer:
3 moles of NH₄Cl
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
NH₃(g) + HCl(g) → NH₄Cl(s) ΔH = –176 kJ
From the balanced equation above,
1 mole of NH₄Cl where obtained when the change in enthalphy (ΔH) was –176 kJ.
Finally, we shall determine the number of mole of NH₄Cl produced when the change in enthalphy (ΔH) is –528 kJ. This can be obtained as follow:
From the balanced equation above,
1 mole of NH₄Cl where obtained when the change in enthalphy (ΔH) was –176 kJ.
Therefore, Xmol of NH₄Cl will be obtained when the change in enthalphy (ΔH) is –528 kJ i.e
Xmol of NH₄Cl = –528 / –176
Xmol of NH₄Cl = 3 moles
Thus, 3 moles of NH₄Cl where obtained from the reaction.
