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Yakvenalex [24]
3 years ago
13

Which environmental conditions contribute most to the spread of bacteria?

Chemistry
1 answer:
Nostrana [21]3 years ago
6 0
Answer: D

Explanation: Bacteria thrives in warm and moist environments.
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Understanding atoms elements and compounds
zavuch27 [327]
What about understanding atoms and compounds?
8 0
3 years ago
How much heat is added if 0.5137g of water increases in temperature by 0.871 degrees C?
UNO [17]

Answer:

1.87 J

Explanation:

q = c x m x (T2-T1)

c- specific heat of water (4.186 j/g.C)

q = 4.186 x 0.5137 x 0.871 = 1.87 J

8 0
3 years ago
How many molecules are in 3.8 mols of copper?
ioda

Answer:

Hi there!

The correct answer is 2.29 x 10^{24} molecules

Explanation:

To convert from the moles to molecules:

1 mole = 6.022 x 10²³ molecules

so basically you multiply 3.8 by 6.022 x 10²³

and you get: 2.29 x 10^{24}

5 0
4 years ago
A compound contains 75% carbon and 25% hydrogen by mass. what is the empirical formula for this compound?
Lady bird [3.3K]
These percentages are most likely mass percentages. Therefore, determine the mass of each element in 100g of the compound. 

<span>75g C, 25g H. </span>

<span>Divide these masses by their molar mass to find the ratios of the moles of element in the compound. Divide these values by the smallest of the two/three to get the ratios. </span>

<span>6.25:25 C:H --> 1:4 </span>


<span>So the formulae are CH4 (methane).</span>
4 0
3 years ago
Read 2 more answers
Q2.
Serga [27]

Answer:

266 liters Carbon iv oxide will be formed

Explanation:

The first thing we need to do here is to calculate the number of moles of oxygen reacted.

This can be calculated using the ideal gas equation;

Mathematically;

PV = nRT

From the question;

P = pressure = 10.5 atm

V = volume = 400 liters

n = number of moles = ?

T = temperature = 125 + 273 = 398K

R = molar gas constant = 0.0821 L•atm•K^-1•mol^-1

Substituting these values, we have ;

n = PV/RT

n = (10.25 * 400)/(398 * 0.0821) = 125 moles

From the question;

15 moles oxygen gave 10 moles CO2

125 moles oxygen will give x moles CO2

x = (125 * 10)/15 = 83 moles

Now, we want to know the volume of CO2, present in 83 moles using the given reaction conditions.

Mathematically;

PV = nRT

V = nRT/P

= (83 * 0.0821 * 398)/10.25 = 265.65 which is approximately 266 Liters

4 0
3 years ago
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