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valentinak56 [21]
3 years ago
11

The area of a circle is 38.5 cm². Calculate.(a) the radius​

Chemistry
2 answers:
prisoha [69]3 years ago
7 0

The Answer is 3.501591994

STatiana [176]3 years ago
5 0

Explanation:

area of circle = πr^2

radius=

39.5 = 22/7*r^2

r^2 = 7*39.5/22

= 12.56

r=3.5

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A 0.04328 g sample of gas occupies 10.0-mL at 294.0 K and 1.10 atm. Upon further analysis, the compound is found to be 25.305% C
stepan [7]

Answer:

<u>The molecular formula of the gas sample = C_2Cl_2 </u>

<u>Lewis structure is shown in the image below.</u>

<u>The geometry around each carbon atom is linear.</u>

Explanation:

Given that:

Temperature = 294.0 K

V = 10.0 mL = 0.01 L ( 1 mL = 0.001 L )

Pressure = 1.10 atm

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L atm/ K mol  

Applying the equation as:

1.10 atm × 0.01 L = n ×0.0821 L atm/ K mol  × 294.0 K  

⇒n = 0.0004557 mol

Given, mass = 0.04328 g

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.0004557\ mole= \frac{0.04328\ g}{Molar\ mass}

<u>Molar mass of the gas sample = 94.9747 g/mol</u>

Given that:-

% of C = 25.305

Molar mass of C = 12.0107 g/mol

% moles of C = 25.305 / 12.0107 = 2.1069

% of Cl = 74.695

Molar mass of Cl = 35.453 g/mol

% moles of Cl = 74.695 / 35.453 = 2.1069

Taking the simplest ratio for C and Cl as:

2.1069 : 2.1069  = 1 : 1

<u>The empirical formula is = CCl</u>

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,  

Molecular mass = n × Empirical mass

Where, n is any positive number from 1, 2, 3...

Mass from the Empirical formula = 12 + 35.5 = 47.5 g/mol

Molar mass = 94.9747 g/mol

So,  

Molecular mass = n × Empirical mass

94.9747 = n × 47.5

⇒ n = 2

<u>The molecular formula of the gas sample = C_2Cl_2 </u>

Also,

Valence electrons of carbon = 4

Valence electrons of Chlorine = 7  

The total number of the valence electrons  = 4*2 + 7*2 = 22

The Lewis structure is drawn in such a way that the octet of each atom in the molecule is complete. So,  

The Lewis structure is shown in the image below.

According to the theory, the atoms will form a geometry in such a way that there is minimum repulsion and maximum stability.  The carbon atoms are sp hybridized.

<u>So, it is of linear shape.</u>

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3 years ago
How do u find ratios of unknown value
LenaWriter [7]
The simplest ratios compare only two values, but ratios comparing three or more values are also possible. In any situations in which two or more distinct numbers or quantities are being compared, ratios are applicable. By describing quantities in relation to each other, they explain how chemical formulas can be duplicated or recipes in the kitchen expanded.
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3 years ago
What is that the theoretical yield of aluminum oxide I if 3.20 mol of aluminum metal is exposed to 2.70 mole of oxygen
photoshop1234 [79]

Answer:

163.2g

Explanation:

First let us generate a balanced equation for the reaction. This is shown below:

4Al + 3O2 —> 2Al2O3

From the question given, were were told that 3.2moles of aluminium was exposed to 2.7moles of oxygen. Judging by this, oxygen is excess.

From the equation,

4moles of Al produced 2moles of Al2O3.

Therefore, 3.2moles of Al will produce = (3.2x2)/4 = 1.6mol of Al2O3.

Now, let us covert 1.6mol of Al2O3 to obtain the theoretical yield. This is illustrated below:

Mole of Al2O3 = 1.6mole

Molar Mass of Al2O3 = (27x2) + (16x3) = 54 + 48 =102g/mol

Mass of Al2O3 =?

Number of mole = Mass /Molar Mass

Mass = number of mole x molar Mass

Mass of Al2O3 = 1.6 x 102 = 163.2g

Therefore the theoretical of Al2O3 is 163.2g

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Answer:

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