I need an opinion, my other note is in anouther question. what do y'all think.
1 answer:
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For Independent Events, P(A) × P(B) = P(A∩B)
so we have, P(A∩B) = 0.4×0.1 = 0.04
P(A') = 1 - 0.4 = 0.6
This information can be represented on a Venn diagram as shown below
P(A'∪B) means the union of everything that is not A with everything that is B
P(A'∪B) = 0.06 + 0.54 + 0.04 = 0.64
so we have, P(A∩B) = 0.4×0.1 = 0.04
P(A') = 1 - 0.4 = 0.6
This information can be represented on a Venn diagram as shown below
P(A'∪B) means the union of everything that is not A with everything that is B
P(A'∪B) = 0.06 + 0.54 + 0.04 = 0.64