I need an opinion, my other note is in anouther question. what do y'all think.

Mathematics

1 answer:

Alik [6]3 years ago

4 0

Answer:

good job its very good

Step-by-step explanation:

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The lines on a 2-cup liquid measuring cup divide each cup into eighths. If you measure 1 3/4 cups of water, between which two qu

masya89 [10]

Answer:

1 3/4 cups is between the 13th and 15th lines from the bottom.

Step-by-step explanation:

The bottom of the cup has no line and corresponds to 0 eights.

1st line up: 1/8 cup

2nd line up: 2/8 cup this is also called 1/4 cup

3rd line up: 3/8 cup

4th line up: 4/8 cup this is also called 1/2 cup

5th line up: 5/8 cup

6th line up: 6/8 cup this is also called 3/4 cup

7th line up: 7/8 cup

8th line up: 8/8 cup this is also called 1 cup

9th line up: 9/8 cup

10th line up: 10/8 cup this is also called 1 1/4 cup

11th line up: 1 3/8 cup

12th line up: 1 4/8 cup this is also called 1 1/2 cup

13th line up: 1 5/8 cup

14th line up: 1 6/8 cup this is also called 1 3/4 cup

15th line up: 1 7/8 cup

16th line up: 1 8/8 cup this is also called 2 cups

1 3/4 cups is between the 13th and 15th lines from the bottom.

7 0

3 years ago

Number 2 I need help on how to solve it

Hunter-Best [27]

Let's simplify the following expression:

$\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}$

We get,

$\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}$ $\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}$