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3 years ago

What is the solution to the system of equations that is graphed below?

Mathematics

2 answers:

Kaylis [27]3 years ago

6 0

Answer:

jdhfsshdvdvsgjshsgdgdbdhdgdvdbdgdhd

Marianna [84]3 years ago

3 0

Answer:

Show Answer

Step-by-step explanation:

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Cerrena [4.2K]

Answer:

$500

Step-by-step explanation:

$25 = 5% of x

0.05x = 25

x = 25/0.05

x = 500

Answer: $500

4 0

2 years ago

You need 3 sticks of butter for every 24 cookies you bake. How many sticks of butter for 16 cookies

Kay [80]

Answer: 2 sticks.

Step-by-step explanation:

Given statement: You need 3 sticks of butter for every 24 cookies you bake.

Using unitary method , the number of sticks of butter used to bake 1 cookie= $\dfrac{3}{24}=\dfrac{1}{8}$

Then the number of sticks of butter used to bake 1 cookie= $\dfrac{1}{8}\times16=2$

Hence, the number of sticks of butter used to bake 16 cookies= 2

3 0

3 years ago

Read 2 more answers

According to government data, 75% of employed women have never been married. Rounding to 4 decimal places, if 15 employed women

blagie [28]

Answer:

We are given that According to government data, 75% of employed women have never been married.

So, Probability of success = 0.75

So, Probability of failure = 1-0.75 = 0.25

If 15 employed women are randomly selected:

a. What is the probability that exactly 2 of them have never been married?

We will use binomial

Formula : $P(X=r) =^nC_r p^r q^{n-r}$

At x = 2

$P(X=r) =^{15}C_2 (0.75)^2 (0.25^{15-2}$

$P(X=2) =\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{13}$

$P(X=2) =8.8009 \times 10^{-7}$

b. That at most 2 of them have never been married?

At most two means at x = 0 ,1 , 2

So, $P(X=r) =^{15}C_0 (0.75)^0 (0.25^{15-0}+^{15}C_1 (0.75)^1 (0.25^{15-1}+^{15}C_2 (0.75)^2 (0.25^{15-2}$

$P(X=r) =(0.75)^0 (0.25^{15-0}+15 (0.75)^1 (0.25^{15-1}+\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{15-2})$

$P(X=r) =9.9439 \times 10^{-6}$

c. That at least 13 of them have been married?

P(x=13)+P(x=14)+P(x=15)

$={15}C_{13}(0.75)^{13} (0.25^{15-13})+{15}C_{14} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})$

$=\frac{15!}{13!(15-13)!}(0.75)^{13} (0.25^{15-13})+\frac{15!}{14!(15-14)!} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})$

$=0.2360$

8 0

3 years ago

4 1/6 pounds of rice is divided into 5 equal portions. What is the weight in pounds of each portion?

Katen [24]

5/6 or 0.83 lbs is the anwser

4 0

3 years ago

Find f ∘ g f∘g and g ∘ f g∘f. f ( x ) = x 2 / 3 , g ( x ) = x 9 f(x)=x2/3, g(x)=x9 (a) f ∘ g f∘g (b) g ∘ f g∘f Find the domain o

faltersainse [42]

I don’t know it’s soooo long:)

8 0

3 years ago