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KonstantinChe [14]
3 years ago
12

What is the solution to the system of equations that is graphed below?

Mathematics
2 answers:
Kaylis [27]3 years ago
6 0

Answer:

jdhfsshdvdvsgjshsgdgdbdhdgdvdbdgdhd

Marianna [84]3 years ago
3 0

Answer:

Show Answer

Step-by-step explanation:

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3)
Cerrena [4.2K]

Answer:

$500

Step-by-step explanation:

$25 = 5% of x

0.05x = 25

x = 25/0.05

x = 500

Answer: $500

4 0
2 years ago
You need 3 sticks of butter for every 24 cookies you bake. How many sticks of butter for 16 cookies
Kay [80]

Answer: 2 sticks.

Step-by-step explanation:

Given statement: You need 3 sticks of butter for every 24 cookies you bake.

Using unitary method , the number of sticks of butter used to bake 1 cookie=\dfrac{3}{24}=\dfrac{1}{8}

Then the number of sticks of butter used to bake 1 cookie=\dfrac{1}{8}\times16=2

Hence, the number of sticks of butter used to bake 16 cookies= 2

3 0
3 years ago
Read 2 more answers
According to government data, 75% of employed women have never been married. Rounding to 4 decimal places, if 15 employed women
blagie [28]

Answer:

We are given that According to government data, 75% of employed women have never been married.

So, Probability of success = 0.75

So, Probability of failure = 1-0.75 = 0.25

If 15 employed women are randomly selected:

a. What is the probability that exactly 2 of them have never been married?

We will use binomial

Formula : P(X=r) =^nC_r p^r q^{n-r}

At x = 2

P(X=r) =^{15}C_2 (0.75)^2 (0.25^{15-2}

P(X=2) =\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{13}

P(X=2) =8.8009 \times 10^{-7}

b. That at most 2 of them have never been married?

At most two means at x = 0 ,1 , 2

So,  P(X=r) =^{15}C_0 (0.75)^0 (0.25^{15-0}+^{15}C_1 (0.75)^1 (0.25^{15-1}+^{15}C_2 (0.75)^2 (0.25^{15-2}

 P(X=r) =(0.75)^0 (0.25^{15-0}+15 (0.75)^1 (0.25^{15-1}+\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{15-2})

P(X=r) =9.9439 \times 10^{-6}

c. That at least 13 of them have been married?

P(x=13)+P(x=14)+P(x=15)

={15}C_{13}(0.75)^{13} (0.25^{15-13})+{15}C_{14} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})

=\frac{15!}{13!(15-13)!}(0.75)^{13} (0.25^{15-13})+\frac{15!}{14!(15-14)!} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})

=0.2360

8 0
3 years ago
4 1/6 pounds of rice is divided into 5 equal portions. What is the weight in pounds of each portion?
Katen [24]
5/6 or 0.83 lbs is the anwser
4 0
3 years ago
Find f ∘ g f∘g and g ∘ f g∘f. f ( x ) = x 2 / 3 , g ( x ) = x 9 f(x)=x2/3, g(x)=x9 (a) f ∘ g f∘g (b) g ∘ f g∘f Find the domain o
faltersainse [42]
I don’t know it’s soooo long:)
8 0
3 years ago
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