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3 years ago

Solve for A in the equation AB + CD + EFG = Z.

Mathematics

1 answer:

Semenov [28]3 years ago

7 0

Answer:

A = (Z-CD - EFG)/B

Step-by-step explanation:

AB + CD + EFG = Z.

Subtract CD and EFG from each side

AB + CD + EFG-CD -EFG = Z-CD - EFG

AB = Z-CD - EFG

Divide each side by B

AB /B = (Z-CD - EFG)/B

A = (Z-CD - EFG)/B

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Last year a baseball team paid $20 per bat and $12 per glove spending a total of $1040 this year the prices went up to $25 per b

Sonja [21]

<span>20x + 12y = 1040
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-12y' to each side of the equation. 20x + 12y + -12y = 1040 + -12y Combine like terms: 12y + -12y = 0 20x + 0 = 1040 + -12y 20x = 1040 + -12y Divide each side by '20'. x = 52 + -0.6y
thats the first part
then we have
</span>25x + 16y = 1350
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-16y' to each side of the equation.
25x + 16y + -16y = 1350 + -16y
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3 years ago

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3 years ago

Read 2 more answers

Math question #1 please show steps

-Dominant- [34]

Answer:

Step-by-step explanation:

An approximation of an integral is given by:

$\displaystyle \int_a^bf(x)\, dx\approx \sum_{k=1}^nf(x_k)\Delta x\text{ where } \Delta x=\frac{b-a}{n}$

First, find Δx. Our a = 2 and b = 8:

$\displaystyle \Delta x=\frac{8-2}{n}=\frac{6}{n}$

The left endpoint is modeled with:

$x_k=a+\Delta x(k-1)$

And the right endpoint is modeled with:

$x_k=a+\Delta xk$

Since we are using a Left Riemann Sum, we will use the first equation.

Our function is:

$f(x)=\cos(x^2)$

Therefore:

$f(x_k)=\cos((a+\Delta x(k-1))^2)$

By substitution:

$\displaystyle f(x_k)=\cos((2+\frac{6}{n}(k-1))^2)$

Putting it all together:

$\displaystyle \int_2^8\cos(x^2)\, dx\approx \sum_{k=1}^{n}\Big(\cos((2+\frac{6}{n}(k-1))^2)\Big)\frac{6}{n}$

Thus, our answer is C.

*Note: Not sure why they placed the exponent outside the cosine. Perhaps it was a typo. But C will most likely be the correct answer regardless.

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3 years ago

A wheel has a radious of 50cm. How many times would the wheel go around if it rolled for 10km

Zinaida [17]

First you must make sure all measurements are in the same value: You can choose either cm or km

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1,000,000/(2π*50)

1,000,000/314.059…….

Approx = 3183.1 Rotations

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2 years ago

Exhibit 12-4 In the past, 35% of the students at ABC University were in the Business College, 35% of the students were in the Li

Brums [2.3K]

Answer:d. uniformly distributed variable

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When we see the percentage of how these students are distributed in art college and business college it is likely that one obtains a uniform distributed results.

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3 years ago