If the line segment point is D(-5, 10) and E(a,b) and the midpoint of the segment is F(13, -2) that mean
DE= 2*DF
You can directly find the distance of AC
Xdf= Xf-Xd= 13 - (-5)= 18
Ydf= Yf - Yd= -2 - 10= -12
Then add the distance of AB( which is 2*AC) to point D
Xe= a = Xd + 2*Xdf
a= -5 +2*18= 31
Ye= b = Yd + 2Yf
b= 10+ 2*-12= -14
<span>absolute difference between a and b:
|b-a|= </span>|-14-31|= 45
Hey there!!
Scientific notation of 0.000000001 :
0.1 ⁻⁷
Hope it helps!
Answer: 12
Explain: Hope this helps!
Since AB = CD the trapezoid is isosceles, which means that ∡A = ∡D
Therefore also ∡2 = ∡3 (they are half of the congruent angles)
For the properties of parallel lines (BD and AD) crossed by a transversal (BD) we have ∡3 = ∡CBD.
Now consider triangles AOD and BCD:
∡OAD (2) = ∡ADO (3) = ∡CBD (3) = ∡CDB (4)
T<span>he sum of the angles of a triangle must be 180°, t</span>herefore:
∡AOD = 180 - ∡2 - ∡3
∡BCD = 180 - ∡3 - ∡4
∡AOD = ∡BCD because their measure is the difference of congruent angles.
