Question

What is the slope for 1.(4,9) & (1,6)

Answer 1

Step-by-step explanation:

1.(4,9) & (1,6)

m=y²-y¹/x²-x¹

m=6-9/1-4

m=-3/-3

m= 1

2.(5,3) & (5,-9)

m=y²-y¹/x²-x¹

m=(-9)-3/5-5

m=-12/0

3.(2,1) & (8,9)

m=y²-y¹/x²-x¹

m=9-1/8-2

m=8/6

m= 4/3

4.(14,-8) & (7,-6)

m=y²-y¹/x²-x¹

m=(-6)-(-8)/7-14

m=2/-7

m= -2/7

5.(4,-3) & (8,-3)

m=y²-y¹/x²-x¹

m=(-3)-(-3)/8-4

m=0/4

m=0

6.(-11,1) & (-2,6)

m=y²-y¹/x²-x¹

m=6-1/(-2)-(-11)

m=5/9