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zubka84 [21]
3 years ago
5

What is the equation of the line that passes through the point (-2, -2) and has a slope of 4?

Mathematics
1 answer:
a_sh-v [17]3 years ago
4 0

Answer:

m

=

5

,

(

1

,

1

)

3

,

(

2

,

9

)

7

,

(

−

2

,

−

9

)

Step-by-step explanation:

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If the measure of angle 2 is 92 degrees and the measure of angle 4 is (1/2x) degrees what is the value of x?
bekas [8.4K]

multiply 92 times .5 and you get 184


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Probably 5 because it only states 1 firework
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What value of x will make parallelogram ABCD a rhombus?
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I WILL GIVE YOU BRAINLIEST, AND 30 POINTS SO PLEASE HELP ME, IT'S URGENT!
IRINA_888 [86]

Answer:

<em>Answer is option</em><em> </em><em>b</em><em>)</em><em> </em>

<em>{(x - 3)}^{2}  +  {(y - 4)}^{2}  = 400</em>

<em>Your</em><em> </em><em>guess</em><em> </em><em>was</em><em> </em><em>right</em><em>.</em>

Step-by-step explanation:

the \: question \: states \: that \:  \\ distance \: between \: two \: points \: is \: 20 \: units \:  \\ and \: the \: two \: points \: are \: (x,y) \:  \: and \:  \: (3 ,- 4) \\ distance \: formula \\  =   \sqrt{ {(x1 - x2) }^{2} +  {(y1 - y2)}^{2}  }  \\ on \: substituting \: the \: values \: in \: formula \\ 20 =  \sqrt{ {(x - 3)}^{2} +  {(y - ( - 4))}^{2}  }  \\ 20 =  \sqrt{ {(x - 3)}^{2} +  {(y + 4)}^{2}  }  \\ now \: squaring \: on \: both \: sides \\ 400 =  {(x - 3)}^{2}  +  {(y + 4)}^{2}  \\ hence \: the \: answer \: is \: option \: b)

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

6 0
3 years ago
A circle centered at the origin contains the point (0,-9). Does (8, sqr 17) also lie on the circle?
Reptile [31]

Check the picture below.

since the circle is centered at the (0,0) origin, and a point on it is at (0, -9), its radius is simple the distance between those two, or r = 9.

if the second point is also on the circle, it must also be 9 units away from the origin.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{\sqrt{17}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{(8-0)^2+(\sqrt{17}-0)^2}\implies d=\sqrt{8^2+(\sqrt{17})^2} \\\\\\ d=\sqrt{64+17}\implies d=\sqrt{81}\implies d=9~~\textit{\Large \checkmark}

7 0
3 years ago
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